Algebra Test

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Algebra Test - 3

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Weekly Quiz Competition

Question 1
1 / -0

If a traveller travels x km in total and travels 3y km by car, 7z km on foot and the rest by bus, then which of the following represents the distance covered by bus?

A
x - y - z

B
x - 7y - 3z

C
x + 3y + 7z

D
x - 3y - 7z

Solution

According to the question:
The traveler travels x km in total, and travels 3y km by car, 7z km on foot and the rest by bus.
So, distance covered by bus =Total - Traveled by car - Traveled on foot
= x - 3y - 7z
Question 2
1 / -0

Gursimran weighs 76 kg. Balkaran weighs 'Z' kg less than him. What is their total weight?

A
152 + Z

B
76 + Z

C
152 - Z

D
76 - Z

Solution

Gursimran's weight = 76 kg
Balkaran's weight = (76 - Z) kg
Total weight = 76 + (76 - Z)
= 152 - Z
Question 3
1 / -0

Lovepreet has some packets of chocolates containing 25 chocolates each. Out of them, he gives 9 packets to Konark.

Which of the following expressions shows the number of chocolates left with Lovepreet?

Y = Number of packets of chocolates

A
25Y = 220

B
25Y x 9 = 225

C
25Y + 225

D
25Y - 225

Solution

Number of chocolates in a packet = 25
Number of chocolates in Y packets = 25Y
Number of chocolates left = 25Y - 25 x 9
= 25Y - 225
Question 4
1 / -0

Livie got 45 all types of sweets. The number of chocolates and candies with Livie are 8 less and 4 more than the number of toffees, respectively. If the number of toffees is 'R', then what sentence can be used to represent the total sweets with Livie?

A
45 = R - (R - 8 ) - (R + 4)

B
45 = R + (R - 8 ) + (R + 4)

C
45 = R - (R + 8 ) + (R + -4)

D
45 = R + (R + 8 ) - (R -4)

Solution

Number of toffees= R
Number of chocoaltes= R - 8
Number of candies= R + 4
Total number of sweets (45) = R + R - 8 + R + 4
Question 5
1 / -0

Fill in the blanks.

(I) Something with a fixed value is called _____J_____.
(ii) 9 less than thrice of 'F' will be ____K_____.
(iii) A concept that shows correlation is called _____L_____.

J K L

a. ratio 3F + 9 constant

b. constant 3F - 9 ratio

c. ratio 3F - 9 constant

d. constant 3F + 9 ratio

A
a

B
b

C
c

D
d

Solution

(i) Something with a fixed value is called constant.
(ii) 9 less than thrice of 'F' will be 3F - 9.
(iii) A concept that shows correlation is called ratio.
Question 6
1 / -0

State true (T) or false (F).

(J) Comparative relation between things or magnitudes as to size, quantity, number, etc is called ratio.
(K) Z = 21 is the solution of equation 75 - Z = 54.
(L) Something with a fixed value is called variable.

J K L

a. F F F

b. T T F

c. T F T

d. F T T

A
a

B
b

C
c

D
d

Solution

J) Comparative relation between things or magnitudes as to size, quantity, number, etc is called ratio.

(K) Z= 21 is the solution of equation 75 - Z = 54.

=> Putting value;
75 - 21= 54

(L) Something with a fixed value is not called variable; it is called constant.

Question 7

1 / -0

Match the following:

A	B
(i)The value of 'y' is 21 more than four times the value of x.	(a) K + 9
(ii) Emma has Rs. G, which she distributes among her 4 friends fairly. The amount of money with each friend is ______.	(b) y = 21 + 4x
(iii) Neha has 'K' chocolates. Her sister gives her 9 more. How many chocolates does she have now?	(c) G/4

(i) - (c), (ii) - (b), (iii) - (a)

(i) - (c), (ii) - (a), (iii) - (b)

(i) - (a), (ii) - (b), (iii) - (c)

(i) - (b), (ii) - (c), (iii) - (a)

Solution

(i) The value of 'y' is 21 more than four times the value of x.
=> y = 21 + 4x

(ii) Emma has Rs. G, which she distributes among her 4 friends fairly. The amount of money with each friend is G/4.

(iii) Neha has 'K' chocolates. Her sister givesher 9 more. How many chocolates does she have now?
=> K + 9

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Re-Attempt Weekly Quiz Competition

J	K	L
a. ratio	3F + 9	constant
b. constant	3F - 9	ratio
c. ratio	3F - 9	constant
d. constant	3F + 9	ratio

Algebra Test - 3

Result

Algebra Test - 3

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SHARING IS CARING

Question 1

x - y - z

x - 7y - 3z

x + 3y + 7z

x - 3y - 7z

Solution

Question 2

152 + Z

76 + Z

152 - Z

76 - Z

Solution

Question 3

25Y = 220

25Y x 9 = 225

25Y + 225

25Y - 225

Solution

Question 4

45 = R - (R - 8 ) - (R + 4)

45 = R + (R - 8 ) + (R + 4)

45 = R - (R + 8 ) + (R + -4)

45 = R + (R + 8 ) - (R -4)

Solution

Question 5

a

b

c

d

Solution

Question 6

a

b

c

d

Solution

Question 7

(i) - (c), (ii) - (b), (iii) - (a)

(i) - (c), (ii) - (a), (iii) - (b)

(i) - (a), (ii) - (b), (iii) - (c)

(i) - (b), (ii) - (c), (iii) - (a)

Solution

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