Decimals Test

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Decimals Test - 12

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Weekly Quiz Competition

Question 1
1 / -0

If 0.1111111 is approximately equal to , then the approximate value of 0.5555555 is

A

B

C

D

Solution

We have, 0.1111111 =

Now, 0.1111111 × 5 = × 5
i.e. 0.5555555 =
Question 2
1 / -0

Directions: Arrange the following decimal numbers in descending order.

0.8, 0.75, 0.89, 0.08, 0.82

A
0.8, 0.75, 0.89, 0.82, 0.08

B
0.89, 0.82, 0.8, 0.75, 0.08

C
0.08, 0.75, 0.8, 0.82, 0.89

D
0.08, 0.8, 0.75, 0.82, 0.89

Solution

Descending order: Arranged from largest to smallest.

0.89, 0.82, 0.8, 0.75, 0.08
Question 3
1 / -0

Which of the following is wrong?

A
0.8 =

B
0.75 =

C
0.5 >

D
0.70 > 0.07

Solution

1) 0.8 = is not equal to

2) 0.75 =

3) 0.5 =
= 0.25

So, 0.5 > 0.25

4) 0.70 =
0.07 =

So, 0.70 > 0.07
Question 4
1 / -0

In an amusement park, Rs. 100 is charged for admission and the visitors have to pay separately for each ride. A person spends Rs. 1,200 in total and went on 8 rides. The expression which can be used is 1,200 = 100 + 8R, where R = Cost of each ride.

Find the cost of each ride.

A
Rs. 133.33

B
Rs. 132.22

C
Rs. 137.50

D
Rs. 135.25

Solution

We have,

1,200 = 100 + 8R

8R = 1,200 - 100

R = = Rs. 137.50
Question 5
1 / -0

If we subtract the sum of 256.6 and 125.36 from the sum of 325.54 and 212.60, then the resulting number will be

A
156.18

B
154.25

C
128.62

D
130.45

Solution

325.54 + 212.60 = 538.14
256.6 + 125.36 = 381.96
Difference = 538.14 - 381.96
= 156.18
Question 6
1 / -0

Directions: Find the biggest decimal number among the following options.

A
0.5055

B
0.5

C
0.05

D
0.555

Solution

The biggest decimal number among the given options is 0.555.
Question 7
1 / -0

Find the value of
0.00005627 - 0.00000001564 x 1502 + 0.00000789124.

A
0.00004066996

B
0.07452652

C
0.00556468

D
0.26359862

Solution

0.00005627 - 0.00000001564 x 1502 + 0.00000789124
= 0.00004066996
Question 8
1 / -0

Solve 5.264 x 5.26 x 3.03 x 0.2 x 0.0.

A
0

B
1.65

C
2.64

D
16.77

Solution

Any number multiplied by zero is always equal to zero.
5.264 x 5.26 x 3.03 x 0.2 x 0.0 = 0
Question 9
1 / -0

Which of the following is incorrect?

A
5 tenths and 6 hundredths = 0.56

B
15 tenths and 16 hundredths = 0.1516

C
25 tenths and 26 hundredths = 2.76

D
35 tenths and 36 hundredths = 3.86

Solution

1. 5 tenths and 6 hundredths == 0.56
2. 15 tenths and 16 hundredths == 1.66 (Incorrect)
3. 25 tenths and 26 hundredths == 2.76
4. 35 tenths and 36 hundredths == 3.86
Question 10
1 / -0

Directions: Select the correct option which will make the given expression true.

4.5 + 3.6 + 6 - 7 ____ 3.7 + 1.5 + 13.5

A
>

B
<

C
=

D
Can't be determined

Solution

We have,
4.5 + 3.6 + 6 - 7
= 4.5 + 3.6 + 6.75 - 7.2
= 14.85 - 7.2
= 7.65
And, 3.7 + 1.5 + 13.5 = 18.7
So, 7.65 < 18.7.
Question 11
1 / -0

Hari says that sum of two numbers is 43.060. If one of them is 31.66, then find the other number.

A
15

B
13.5

C
12

D
11.4

Solution

Let the other number be x.
According to question,
31.66 + x = 43.060
x = 43.060 – 31.66
= 11.4
Question 12
1 / -0

What is the difference between the length of car A and B?

A
10 cm

B
8 cm

C
7 cm

D
5 cm

Solution

Length of car A = 7 cm
Length of car B = 15 - 3 = 12 cm
Difference = 12 - 7 = 5 cm
Question 13
1 / -0

Joy is adding 22.680 + 1.20 + 55 and he wants to round-off the answer to the nearest tenths. What will be the number?

A
78

B
78.8

C
78.9

D
80

Solution

22.680 + 1.20 + 55 = 78.88
78.88 rounded-off to the nearest tenths = 78.9
Question 14
1 / -0

If 0.80 of a number is 1680, then what will beof that number?

A
3150

B
3300

C
3455

D
3600

Solution

Let the number be a.

a x= 1680

a = 2100
Now, 2100 x= 3150
Question 15
1 / -0

Which of the following fractions corresponds to the given number?

2 hundreds + 6 tens + 3 ones + 4 tenths + 4 hundredths

A

B

C

D

Solution

2 hundreds + 6 tens + 3 ones + 4 tenths + 4 hundredths

= 2 x 100 + 6 x 10 + 3 x 1 +

= 200 + 60 + 3 + 0.4 + 0.03

= 263.43

=
Question 16
1 / -0

In which figure does the shaded part represent 0.25?

A

B

C

D

Solution

Option 1: 1 out of 2 parts are shaded = = 0.5
Option 2: 4 out of 6 parts are shaded = = 0.66
Option 3: 4out of 8 parts are shaded == = 0.5
Option 4: 4 out of 16 are shaded === 0.25
Question 17
1 / -0

Find the value of 4 + (9.01 + 8) + (9.001 + 6) + (9.0001 + 9).

A
50.012

B
54.0111

C
55.1436

D
56.0145

Solution

4 + (9.01 + 8) + (9.001 + 6) + (9.0001 + 9)
= 4 + (17.01) + (15.001) + (18.0001)
= 4 + (50.0111)
= 54.0111
Question 18
1 / -0

Directions: The following circle has been divided into several parts. The shaded parts represent people who own cars and the people who do not own cars are represented by the unshaded parts. Find the decimal fraction of the people who do not own a car.

A
0.4

B
0.6

C
0.8

D
1

Solution

Total parts in which the circle is divided = 10
People who own a car = 4
People who do not own a car = 6
Now, decimal fraction of the people who do not own a car == 0.6
Question 19
1 / -0

Find the value of the given expression.

A
101.1

B
10.1

C
101.01

D
202.002

Solution

10 +=
=
= 10.1
Question 20
1 / -0

Which of the following is the decimal form of?

A
897.53

B
89.753

C
890.753

D
890.0753

Solution

=

= 89.753
Question 21
1 / -0

A shopkeeper delivered 8.5 kg of curd, 9.7 kg of pure ghee, 15.25 kg of paneer and 3.75 kg of butter. Find the total weight of all the things that were delivered.

A
32.4 kg

B
37.2 kg

C
35.5 kg

D
34.2 kg

Solution

Weight of curd = 8.5 kg
Weight of pure ghee = 9.7 kg
Weight of paneer = 15.25 kg
Weight of butter = 3.75 kg
Total weight = 8.5 + 9.7 + 15.25 + 3.75
= 37.2 kg
Question 22
1 / -0

Amar had Rs. 550 in total. He bought an item for Rs. 329.40 and kept Rs. 10 for travelling. How much money is left with him?

A
Rs. 215.40

B
Rs. 200

C
Rs. 210.60

D
Rs. 220.60

Solution

Total money Amar had = Rs. 550
Money spent on an item = Rs. 329.40
Money spent on travelling = Rs. 10
Money left with him = 550 - (329.40 + 10)
= Rs. 210.60
Question 23
1 / -0

Karan's office is 12 km from home. He goes to temple before going to office, which is on the way. The temple is 3 km 700 m from his home. How much does he need to travel further from the temple to reach his office?

A
15.7 km

B
9 km

C
8.3 km

D
20.3 km

Solution

Total distance travelled = 12 km
Distance travelled to temple = 3.7 km
So, distance left to be travelled = 12 - 3.7 = 8.3 km or 8 km 300 m
Question 24
1 / -0

Shweta bought 3 packets of pencils for Rs. 12.5 each, 5 packets of erasers for Rs. 7.50 each and 1 box of sharpeners for Rs.17. How much did she need to pay the shopkeeper?

A
Rs. 87

B
Rs. 92

C
Rs. 112

D
Rs. 153

Solution

Cost of 1 packet of pencils = Rs. 12.5
Cost of 3 packets of pencils = Rs. 12.5 × 3 = Rs. 37.5
Cost of 1 packet of erasers = Rs. 7.50
Cost of 5 packets of erasers = Rs. 7.50 × 5 = Rs. 37.5
Cost of 1 box of sharpeners = Rs. 17
Total cost = 37.5 + 37.5 + 17 = Rs. 92
Question 25
1 / -0

If a pack of 8 footballs is bought for Rs. 5,250, then what would be the cost of 1 football?

A
Rs. 650.35

B
Rs. 645.35

C
Rs. 656.25

D
Rs. 666.65

Solution

Cost of 8 footballs = Rs. 5,250

Cost of 1 football = = Rs. 656.25

Question 26

1 / -0

Find the values of A, B and C.

(1) 69 hundredths have 6 tenths and __A__ hundredths.
(2) Rounding off 4.732 to 2 decimal places will give __B__.
(3)can be written as __C__.

	A	B	C
(i)	60	4.70
(ii)	9	4.74
(iii)	9	4.73
(iv)	69	4.80

iv

ii

iii

i

Solution

(1) 69 hundredths = = 0.69, i.e. 6 tenths and 9 hundredths.

(2) 4.732 rounded off to 2 decimal places would be 4.73 (Because it is the nearest number to 2 decimal places).

(3) ^{Hence, option (3) is correct.}

Question 27

1 / -0

State 'T' for true and 'F' for false for the following statements.

(i) 1 tens plus 2 ones plus 3 tenths and 4 hundredths can be written as 12.34.
(ii) The shortest form to writeis.
(iii) A fraction whose denominator is 10 or is a multiple of 10 is called a simple fraction.

	(i)	(ii)	(iii)
1	F	F	T
2	T	T	F
3	F	T	F
4	T	F	T

3

1

2

4 Solution

(1) 1 tens plus 2 ones plus 3 tenths and 4 hundredths = 10 + 2 + 0.3 + 0.04 = 12.34 (True)
(2) The shortest form to writeis. (True)
(3) A fraction whose denominator is 10 or a multiple of 10 is called a decimal fraction. (False)

Question 28

1 / -0

Directions: Match the following.

Column I	Column II
1. 1480 + 200 + 0.025	p. 150.8
2. 10 + 0.8 + 140	q. 359.57
3. 490 + 20 + 3.283	r. 1680.025
4. 151 + 125.22 + 83.35	s. 513.283

1 - p, 2 - q, 3 - r, 4 - s

1 - s, 2 - r, 3 - q, 4 - p

1 - r, 2 - p, 3 - s, 4 - q

1 - r, 2 - s, 3 - p, 4 - q

Solution

1. 1480 + 200 + 0.025 = 1680.025
2. 10 + 0.8 + 140 = 150.8
3. 490 + 20 + 3.283 = 513.283
4. 151 + 125.22 + 83.35 = 359.57

Question 29
1 / -0

Directions: Select the incorrect statement.

1. A milkman has 59 litres of milk. He sold 19 litres to one person and 28,500 ml to another person. Milk left with him is 11,500 ml.
2. Sohan bought some bundles of copies. 1 bundle weighs 2870 gm, 2 other bundles weigh 1.4 kg. The total weight is 5.67 kg.
3. Suresh spent Rs. 439.30 on grocery and Rs. 139.50 on soft drinks. If he has exactly the double of what he spent, then the money he had in the beginning was Rs. 1157.6.
4. Amar travelled 9 km by bus and 3 km by auto to his college and then returned home. If he travelled 5 days in a week, then the total distance travelled by him is 60 km.

A
2

B
3

C
4

D
1

Solution

1. Quantity of milk sold = 19 + 28.5 = 47.5 litres
Quantity of milk left with milkman = 59 - 47.5
= 11.5 litres or 11,500 ml (Correct)

2. Total weight of all the bundles of copies = 1.4 + 1.4 + 2.87 = 5.67 kg (Correct)

3. Money spent on grocery and soft drinks = 439.30 + 139.50 = Rs. 578.8
Amount of Money that Suresh had in the beginning = 578.8 x 2 = Rs. 1157.6 (Correct)

4. Distance travelled by Amar from home to college = 9 + 3 = 12 km
Distance travelled by coming back to home from college = 12 km
Total distance travelled in 1 day = 12 + 12 = 24 km
Total distance travelled in 5 days = 24 x 5 = 120 km or 120,000 m.
Therefore, statement 4 is incorrect.
Question 30
1 / -0

Directions: Read the following statements and choose the correct option.

Statement 1: 0.368 + 9.721 + 2.3 - 4.75 > 0.236 + 8.999 + 2.23 - 3.867
Statement 2: If while comparing decimal numbers, one number is in hundredths and the other is in thousandths, then the number with thousandths is always bigger.

A
Both statements are true.

B
Statement 1 is false and 2 is true

C
Statement 1 is true and 2 is false.

D
Both statements are false.

Solution

Statement 1: 0.368 + 9.721 + 2.3 - 4.75 = 7.639
0.236 + 8.999 + 2.23 - 3.867 = 7.598
So, 7.639 > 7.598

Statement 2: 1.23 is the first number and 1.139 is second. So, it is not always that the number with thousandths is always bigger.

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Re-Attempt Weekly Quiz Competition

Decimals Test - 12

Result

Decimals Test - 12

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Question 1

Solution

Question 2

0.8, 0.75, 0.89, 0.82, 0.08

0.89, 0.82, 0.8, 0.75, 0.08

0.08, 0.75, 0.8, 0.82, 0.89

0.08, 0.8, 0.75, 0.82, 0.89

Solution

Question 3

0.8 =

0.75 =

0.5 >

0.70 > 0.07

Solution

Question 4

Rs. 133.33

Rs. 132.22

Rs. 137.50

Rs. 135.25

Solution

Question 5

156.18

154.25

128.62

130.45

Solution

Question 6

0.5055

0.5

0.05

0.555

Solution

Question 7

0.00004066996

0.07452652

0.00556468

0.26359862

Solution

Question 8

0

1.65

2.64

16.77

Solution

Question 9

5 tenths and 6 hundredths = 0.56

15 tenths and 16 hundredths = 0.1516

25 tenths and 26 hundredths = 2.76

35 tenths and 36 hundredths = 3.86

Solution

Question 10

>

<

=

Can't be determined

Solution

Question 11

15

13.5

12

11.4

Solution

Question 12

10 cm

8 cm

7 cm

5 cm

Solution

Question 13

78

78.8

78.9