Mensuration Test

Result

Mensuration Test - 3

Score
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Rank
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Weekly Quiz Competition

Question 1
1 / -0

Ali walks four times around a rectangular field of length 5 m and breadth 8 m. Benny walks thrice around a square field of side 15 m. Who covered more distance and by how much?

A
Benny, 76 m

B
Benny, 56 m

C
Ali, 56 m

D
Ali,76 m

Solution

Perimeter of rectangular field = 2( l + b) = 2(5 + 8) = 2 x 13 = 26 m

Ali walked 4 times = 4 x 26 = 104 m

Perimeter of square field = 4 (side) = 4 x 15 = 60 m

Benny walked 3 times = 3 x 60 = 180 m

Difference = 180 - 104 = 76 m

So, Benny covered more distance than Ali by 76 m.
Question 2
1 / -0

Deny wants to put a fence around his garden of length 12 m and breadth 15 m. Find the total cost of fencing at the rate of Rs. 20 per metre.

A
Rs. 900

B
Rs. 970

C
Rs. 1030

D
Rs. 1080

Solution

Perimeter of garden = 2(l + b) = 2(12 + 15) = 54 m
Cost of fencing per metre = Rs. 20
Cost of fencing 54 metres = 54 × 20 = Rs. 1080
Question 3
1 / -0

What is the distance covered by John, if he walks 30 rounds of a park of equilateral triangle shape of side 18 m?

A
1620 m

B
1650 m

C
1670 m

D
1700 m

Solution

Length of each side of a park = 18 m
Perimeter of the given park = 3 x 18 = 54 m
Distance covered by John in rounds = 30 x 54 = 1620 m
Question 4
1 / -0

Usain Bolt takes 50 rounds of square park of side 25 m. What is the total distance covered by him?

A
5000 m

B
1000 m

C
4000 m

D
2000 m

Solution

Side of a square park = 25 m
Perimeter of the park = sum of all sides = 25 + 25 + 25 + 25 = 100 m
So the total distance travelled by Usain Bolt in 50 rounds = 50 x 100 = 5000 m
Question 5
1 / -0

Find the values of P, Q, R and S

Length of rectangle
Cm Breadth of rectangle
Cm Area
Cm² Perimetor
Cm

12 P 144 Q

R 24 S 68

A
(P) 132 cm, (Q) 48 cm, (R) 10 cm, (S) 240 cm²

B
(P) 12 cm, (Q) 48 cm, (R) 20 cm, (S) 240 cm²

C
(P) 12 cm, (Q) 48 cm, (R) 10 cm, (S) 240 cm²

D
(P) 12 cm, (Q) 24 cm, (R) 10 cm, (S) 240 cm²

Solution

(P) 12 cm, as 12 x 12 = 144 cm²

(Q) 48 cm, sum of all sides = 2 x (12 + 12) = 48 cm
(R)10 cm

Perimeter = 68 = 2 x ( x + 24)
68 - 48 = 2x

20 = 2x
x = 10

(S) 240 cm², area of rectangle = l x b = 10 x 24 = 240 cm²