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Comparing Quantities Test - 1

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Comparing Quantities Test - 1
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  • Question 1
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    A family has 3 members - Q, R and S. Ages of Q and R are in the respective ratio of 5 : 9. Ages of R and S are in the respective ratio of 8 : 3. The oldest person among them is 72 years old. Find the difference between the ages of the oldest and the youngest persons in the family.

    Solution

    According to the question:
    Q : R = 5 : 9 ...(i)
    R : S = 8 : 3 ...(ii)

    Multiply (i) by 8 and (ii) by 9 to get the common ratio of Q, R and S.

    The new ratio becomes
    Q : R : S = 40 : 72 : 27
    Let the ages of Q, R and S be 40x, 72x and 27x, respectively.
    The age of the oldest person is 72.
    We can see that R is the oldest.
    Now, 72x = 72, i.e. x = 1

    Age of Q = 40
    Age of R = 72
    Age of S = 27
    Required difference = 72 - 27 = 45

     

  • Question 2
    1 / -0

    Cost of a table is 20% more than that of a chair. By what percentage is table costlier than chair?

    Solution

    The first part of the question tells us that cost of the table is 20% more than that of the chair. It means that the table is 20% costlier than chair.

     

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