Data Handling Test

Result

Data Handling Test - 6

Score
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Rank
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TIME Taken - -

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Weekly Quiz Competition

Question 1

1 / -0

Directions For Questions

Study the given table and answer the following question.

The table shows the population of towns A, B and C in different years:

Years	Town A	Town B	Town C
2011	14,000	45,050	36,540
2012	15,600	46,850	35,980
2013	18,900	47,650	36,000
2014	23,500	50,500	36,500
2015	25,600	51,500	37,000

...view full instructions

What is the difference between the total population of all three towns in 2012 and that in 2015?

20,620

17,690

16,540

15,670

Solution

Total population of all three towns in 2012

= 15,600 + 46,850 + 35,980 = 98,430

Total population of all three towns in 2015

= 25,600 + 51,500 + 37,000 = 1,14,100

So, the required difference

= 1,14,100 - 98,430 = 15,670

Question 2
1 / -0

Find the mode(s) of the following data:

Size 1 21 8 17 4 6 16

Frequency 15 51 16 67 98 98 51

A
1

B
17

C
Both 21 and 16

D
Both 4 and 6

Solution

Mode is the observation which has the highest frequency.

According to the given data, each of 4 and 6 has a frequency of 98, which is the highest.
Question 3
1 / -0

The average height of 7 students is 75 cm. When one student is excluded, the average height of remaining students becomes 72.5. Find the height of the excluded student.

A
70 cm

B
90 cm

C
80 cm

D
100 cm

Solution

Average height of 7 students = 75 cm

So, the sum of the heights of 7 students = 75 × 7 = 525

Average after one student is excluded = 72.5 cm

Total height of 6 students = 72.5 × 6 = 435 cm

So, height of the excluded student = 525 - 435 = 90 cm