Fractions And Decimals Test

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Fractions And Decimals Test - 7

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Weekly Quiz Competition

Question 1
1 / -0

The missing side and perimeter of the given shape, respectively, are

A
cm and cm

B
cm and cm

C
cm and cm

D
cm and cm

Solution

From the diagram:
Let the length of AB be x.

RC = DE
2 + x =
=> x =cm

Perimeter =

=

= cm
Question 2
1 / -0

Find the value of .

A

B

C

D

Solution

=

=
Question 3
1 / -0

21.036, as a fraction, will be written as ______.

A

B

C

D

Solution

=
Question 4
1 / -0

Nisha multiplies a fraction by itself and gets as the result. What is the original fraction?

A

B

C

D

Solution

According to the question:

=>
Question 5
1 / -0

Which of the following statements is true about the given fractions?

A
They all belong to the family of thirds.

B
They are all different.

C
The denominator is 3 more than the numerator.

D
None of these

Solution

All the given fractions belong to the family of thirds, and their denominator is 3 TIMES their numerator. Besides, they all have the same value, i.e. they are equivalent.
Question 6
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What fraction of the given figure is shaded?

A

B

C

D

Solution

Total number of parts = 16

Number of shaded parts = 6

Shaded Fraction =or
Question 7
1 / -0

How many more unit triangles need to be shaded in the figure so that fraction of the shaded squares is?

A
2

B
3

C
4

D
5

Solution

Total number of portions = 36

Number of shaded portions = 12

Shaded Fraction = =
So, to make the fraction of shaded squares , we need to shade 4 more portions.
Then, total number of shaded portions = 12 + 4 = 16

Fraction ==
Question 8
1 / -0

Which of the following options represents of 12 parts shaded?

A
A

B
B

C
C

D
D

Solution

8 parts need to be shaded, which is true for B.
Question 9
1 / -0

Find the value of x:

4123 + 13.765 - x = 4023.002

A
113.763

B
114.435

C
120.112

D
121.998

Solution

4123 + 13.765 - x = 4023.002

4136.765 - x = 4023.002

x = 4136.765 - 4023.002

x = 113.763
Question 10
1 / -0

The quotient obtained when 0.01080 is divided by 0.216 is

A
0.05

B
0.005

C
0.08

D
0.008

Solution

== 0.05
Question 11
1 / -0

Evaluate.

A
6.75

B
5.56

C
3.28

D
2.26

Solution

We have

=

=

=

= = 3.28
Question 12
1 / -0

If the LCM of three numbers is 1651, then what can be their HCF?

A
9

B
13

C
15

D
18

Solution

LCM of three numbers = 1651

As HCF is always a factor of LCM, so LCM must be completely divisible by HCF.

Here, 1651 is completely divisible by 13 only.

So, 13 is the HCF of three numbers.
Question 13
1 / -0

Which of the following options represents 5 x?

A

B

C

D

Solution

5 x =++++

So, option 2 is the answer.
Question 14
1 / -0

Simplify:

A

B

C

D

Solution

= = = =
Question 15
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When 21735 is divided by 161, the quotient obtained is 135. What will be the quotient obtained when 21.735 is divided by 0.0135?

A
1350

B
1610

C
1661

D
1160

Solution

Or
So,= = = 1610
Question 16
1 / -0

69.894 x 891.4 x 0.0088 is the same as _______.

A
6.9894 x 8.914 x 8.8

B
6.9894 x 89.14 x 88

C
69894 x 8914 x 88

D
6989.4 x 8914 x 0.000000088

Solution

69.894 x 891.4 x 0.0088 is the same as 6.9894 x 8.914 x 8.8

As in both the options, the total number of digits after the decimal is 8, therefore on multiplying these numbers, we will get the exact same result.
Question 17
1 / -0

If the numerator and the denominator of a proper fraction are multiplied by the same number, then the resultant fraction would always be

A
greater than the original fraction

B
smaller than the original fraction

C
equivalent to the original fraction

D
None of the above

Solution

If the numerator and the denominator of a proper fraction are multiplied by the same number, then the resultant fraction would always be equivalent to the original fraction.

Suppose is a proper fraction.
Multiplying the numerator and the denominator by 4, it becomes which is same as .
Question 18
1 / -0

The value of 965.5 x 5.1 + 9.6 3.2 is

A
4900.75

B
4854.5

C
4927.05

D
6154.9

Solution

965.5 x 5.1 + 9.6 3.2

= 4924.05 + 3 = 4927.05
Question 19
1 / -0

A shopkeeper has 204 jars. Out of those jars, are filled with different fruits. If of the jars having fruits are filled with apples, then what is the number of jars filled with apples?

A
47

B
51

C
58

D
65

Solution

of 204 = x 204 = 68
That means there are 68 jars filled with fruits.
Now,
number of jars filled with apples = 68 x = 3 x 17 = 51
Question 20
1 / -0

Malkit and Monty together have 81 grams of gold. of Malkit's gold is 18 grams more than of Monty's gold. How much gold does Monty have?

A
36 grams

B
37 grams

C
40 grams

D
35 grams

Solution

Malkit + Monty = 81 grams

of Malkit's gold = 18 + of Monty's gold

Malkit's gold =(18 + of Monty's gold)

Now,

(18 + of Monty's gold) + Monty's gold = 81 grams

27 + Monty's gold + Monty's gold = 81 grams

27 + Monty's gold = 81 grams

Monty's gold = 81 - 27 = 54 grams

Monty's gold = = 36 grams
Question 21
1 / -0

Roger, David, Bally and Mahavir each took part in an archery contest:

Roger hit of the targets.
David hit of the targets.
Bally hit of the targets.
Mahavir hit of the targets.

Who hit the highest fraction of targets among them?

A
Roger

B
David

C
Bally

D
Mahavir

Solution

The fractions are ,, and.

The HCF of 5, 3, 10 and 6 is 30.

So, the fractions become

,, and

The highest fraction out of them is .

So, the person who hit the highest fraction of targets is Mahavir.
Question 22
1 / -0

Priya needs some pieces of ribbon, each of length 85 cm. If the length of a roll of ribbon is 127.5 m, then how many pieces of 85 cm each can she get from it?

A
100

B
150

C
175

D
200

Solution

127.5 m = 127.5 x 100 cm = 12,750 cm

Length of 1 piece = 85 cm

Number of pieces Priya can get == 150
Question 23
1 / -0

A contractor charges Rs. 31.25 per metre for building a wooden fence. If he builds a fence around a playground, with total fenced length as 51 metres, then how much money will he get?

A
Rs. 1451.75

B
Rs. 1509.25

C
Rs. 1593.75

D
Rs. 1629.25

Solution

Fencing cost per metre = Rs. 31.25

Fencing cost for 51 metres = 51 x 31.25 = Rs. 1593.75
Question 24
1 / -0

If 34.5609 = 3P + , then what will be the value of P + Q + 2R + S + T?

A
10546

B
10131

C
10321

D
10422

Solution

34.5609 = 3 × 10 +

Hence, P = 10, Q = 1, R = 10, S = 100, T = 10000
So, P + Q + 2R + S + T = 10 + 1 + 2 × 10 + 100 + 10000 = 10131
Question 25
1 / -0

Which of the following statements is CORRECT?

(A) The product of a proper and an improper fraction is greater than the improper fraction and less than the proper fraction.
(B) While dividing one fraction by another fraction, we multiply the first fraction by the reciprocal of the other.
(C) The reciprocal of a non-zero fraction is obtained by multiplying the numerator by the denominator.
(D) The product of two proper fractions is more than each of the fractions.

A
A

B
B

C
C

D
D

Solution

While dividing one fraction by another fraction, we multiply the first fraction by the reciprocal of the other. For example, ÷ = x
Therefore, statement B is correct.

Question 26

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Kamal and Bimal want to buy 3 mobile phone batteries and a pair of earphones. the below table shows the prices of both the items after implementing some discount.

	Shop A	Shop B	Shop C
1 mobile phone battery	Rs. 449.30	Rs. 400.90	Rs. 449.20
1 pair of earphones	Rs. 330.60	Rs. 340.90	Rs. 250.15

(a) At which shop should Kamal and Bimal shop to spend the least amount of money?
(b) Kamal and Bimal purchased a mobile phone battery from shop A, a pair of earphones from shop C, and one more mobile phone battery from shop B. If they had Rs. 1200 in total, then how much money was left with them?

(a) Shop B (b) Rs. 99.65

(a) Shop A (b) Rs. 99.65

(a) Shop A (b) Rs. 200.65

(a) Shop C (b) Rs. 200.65

Solution

For all four items:

Cost in shop A
= 449.30 x 3 + 330.60
= Rs. 1678.5

Cost in shop B
= 400.9 x 3 + 340.90
= Rs. 1543.6

Cost in shop C
= 449.20 x 3 + 250.15
= Rs. 1597.75

Shop B will cost them the least amount of money.

(b) In this case, they spend = 449.30 + 400.90 + 250.15 = Rs. 1100.35
So, money they will be left with = (1200 - 1100.35) = Rs. 99.65

Question 27
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Directions: Study the given statements and choose the correct option accordingly.

Statement I: Fraction of shaded part of the triangle is .
Statement II: Fraction of shaded part of the star is

A
Both the statements are false.

B
Both the statements are true.

C
Only statement I is true.

D
Only statement II is true.

Solution

Statement I:
Total number of parts = 4
Shaded parts = 2
Fraction of shaded parts = 2/4 = 1/2

Statement II:
Total number of parts = 7
Shaded parts = 3
Fraction of shaded parts = 3/7