Fractions And Decimals Test

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Fractions And Decimals Test - 8

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Weekly Quiz Competition

Question 1
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Directions: Look at the given figure carefully and choose the correct option to fill in the blank.

The perimeters of triangle PQR and quadrilateral QRTS are ____ and ____, respectively.

A
6cm, 7cm

B
9cm, 11cm

C
cm, cm

D
15cm, cm

Solution

(1) Perimeter of PQR = cm
(2) Perimeter of QRST = (2+ 2 + + ) cm = cm
Question 2
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The value of (1 + ) (1 + ) (1 + ) ------- (1 + ) is

A

B

C

D

Solution

(1 + ) (1 + ) (1 + ) ------- (1 + )

= × × × ------- ×

=
Question 3
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The vulgar fraction of 0.539 can be expressed as

A

B

C

D

Solution

0.539 = 0.539 x
=
Question 4
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If we multiply a fraction by itself, then the fraction obtained is . The original fraction is

A
3

B

C

D
1

Solution

Let the original fraction be .
According to question, =

=
Question 5
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The fractions ^,^, and are each equivalent to . Which of the following statements represents the relation between the numerator and denominator of the fractions given above?

A
The numerator is thrice the denominator.

B
The denominator is thrice the numerator.

C
The numerator is 3 more than the denominator.

D
The denominator is 3 more than the numerator.

Solution

We have = = = = , which represents that denominator = 3 x Numerator
Question 6
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What fraction of the figure is shaded?

A

B

C

D

Solution

For each shaped part,
total number of equal parts = 8
Number of shaded parts = 3
Therefore, shaded fraction =
Question 7
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How many more small squares should be shaded in the figure, so that the fraction of shaded squares is ?

A
3

B
4

C
5

D
6

Solution

Total number of small squares = 16
Let the number of shaded squares be x.
As per the question,
=
or, x = × 16
or, x = 10
Out of these 10 squares, 6 have been shaded. So, we need to shade 4 more squares.
Question 8
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Which of the following options represents of 6 parts shaded?

A

B

C

D
None of these

Solution

We know that of 6 = × 6 = 4
Option (1) is correct as 4 parts have been shaded out of 6.
Question 9
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Directions: Find the value of x.

4921 + 14.635 - x = 4883.212

A
52.423

B
52.023

C
53.525

D
54.623

Solution

We have, 4921 + 14.635 - x = 4883.212
4935.635 - x = 4883.212
x = 4935.635 - 4883.212 = 52.423
Question 10
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Which of the following options will give the correct relationship between the given equations?
( - ) - ( × ) + -------- ( - ) -( ÷ ) +

A
>

B
<

C
═

D
Cannot be determined

Solution

L.H.S
( - ) - ( × ) +
= - () +
= - + = =

R.H.S

( - ) -( ÷ ) +
= - () +
= - + = =

Hence, >
Question 11
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When 0.01365 is divided by 0. 273, the quotient is

A
0.04

B
0.05

C
0.005

D
0.008

Solution

0.01365 ÷ 0.273 = x = = 0.05
Question 12
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_Evaluate .

A
23.87

B
2.387

C
0.2387

D
0.02387

Solution

=
=
=
= 23.87
Question 13
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If LCM of four numbers is 9284, then their HCF could be

A
9

B
11

C
13

D
15

Solution

LCM of four numbers is 9284.
As HCF is always a factor of LCM, therefore LCM must be divisible by HCF.
Here, 9284 is divisible by 11 (Using divisibility of 11 rule)
Therefore, HCF could be 11.
Question 14
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Which of the following is the pictorial representation of 4 x ?

A
A

B
B

C
C

D
D

Solution

means three parts are shaded from four.
4 x = + + +
Question 15
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Simplify.

A
16

B
12

C
8

D
4

Solution

=
=
= 4
Question 16
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When 49704 is divided by 327, the quotient is 152. What will be the quotient when 4.9704 is divided by 0.00327?

A
1860

B
1520

C
1485

D
1254

Solution

We know that = 152
=> = x = x 10 = 152 x 10 = 1520
Question 17
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987.326 x 698.6 x 0.191 is the same as

(A) 987326 x 698.6 x 0.191 x 100000

(B) 987326 x 698.6 x 191 x

(C) 987326 x 698.6 x 0.191 x

(D) 987326 x 698.6 x 0.191 x 100 x

A
A

B
B

C
C

D
D

Solution

987.326 x 698.6 x 0.191
= 987326 x 698.6 x 0.191 x
Question 18
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If numerator and denominator of a proper fraction are multiplied by the same quantity, then the resulting fraction is

A
always same as the original fraction

B
always greater than the original fraction

C
always lesser than the original fraction

D
None of these

Solution

If numerator and denominator of a proper fraction are multiplied by the same quantity, then the resulting fraction is always same as the original fraction.
Example:
is multiplied by 3 in both numerator and denominator,
= =
Question 19
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Simplify ÷( + ) of ().

A
()² × 19

B
()² × 23

C
()² × 38

D
()² × 19

Solution

÷ ( + ) of ()
= × ÷ () × ( × )
= 7 ÷ × × 7
= 7 × × × 7
= ()² × 38
Question 20
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The value of 971.5 x 2.4 + 11.6 ÷ 2.9 is

A
2335.6

B
2535.6

C
2575.6

D
2689.5

Solution

971.5 x 2.4 + 11.6 ÷ 2.9
=> +
=> + 4
=> 2331.6 + 4 = 2335.6
Question 21
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Jessica and Logo went for a picnic. Their mother gave them a bottle that contained 5 litres of apple juice. Jessica consumed of the juice. Logo consumed the remaining juice. How much juice did Logo consume?

A
3 litre

B
2 litre

C
1 litre

D
4 litre

Solution

Juice consumed by Jessica = of 5 = litres

Juice consumed by Logo = 5 - 2

= 3 litres
Question 22
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Mahesh wants to put a photograph in a frame. The photograph is cm wide. To fit the photograph in the frame, he needs the size to not be more than cm wide. How much should the photograph be trimmed?

A
cm

B
cm

C
cm

D
cm

Solution

Width of the picture = = cm
Required width = = cm
Required trimming of photograph
⁼^-
= cm
Question 23
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Tarun, Somesh, Bunny and Jagdish took paper reading test. Tarun read of the papers correctly. Somesh read of the paper correctly. Bunny read of the paper correctly and Jagdish read of the paper correctly. Who read maximum papers correctly?

A
Somesh

B
Jagdish

C
Bunny

D
Tarun

Solution

Tarun read ^,Somesh read ^,Bunny read and Jagdish read .
To compare these fractions, take LCM of denominators 8, 16, 4, 20 = 80
^, ^, ^,
Bunny read the maximum papers correctly.
Question 24
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In how many equal parts of 16 cm each will a ribbon of 25.6 m be cut?

A
250

B
240

C
210

D
160

Solution

Total length of ribbon = 25.6 m
Converting it into cm, we get
25.6 × 100 = 2560 cm
We have to cut this length into equal lengths of 16 cm.
Thus, number of equal pieces = 2560 ÷ 16 = 160
Question 25
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Alex drove a car for 156.80 km, consuming 5.8 litres of diesel per km. How much diesel did he use for his entire journey?

A
909.44 litres

B
909.45 litres

C
909.46 litres

D
909.47 litres

Solution

Total distance = 156.80 km
Diesel used per km = 5.8 litres
Total diesel he used for 156.80 km = 156.80 × 5.8 = 909.44 litres
Question 26
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Which of the following statements is incorrect?

A
If there is the same number in the denominator and in the numerator, then it will be equal to one whole number.

B
Improper fraction will be equal to 0.

C
Like fractions have the same denominator.

D
All the unit fractions have a 1 in the numerator.

Solution

Improper fraction is equal to 0.
For example: is an improper fraction.
14 ÷ 5 = 2.8
Question 27
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Directions: Look at the information given carefully and choose the correct answer.

Jack and Sam went to different godowns A, B and C, and bought one sack of rice and one sack of wheat from each of the godowns.

1. At which godown did they spend maximum amount?
2. How much money did they spend for one sack each of rice and wheat in godown A?

A
C, Rs. 811.30

B
C, Rs. 800.30

C
C, Rs. 800.40

D
B, Rs. 800.10

Solution

By looking at the diagram, they spent maximum amount of money at godown C.
Amount of money they both spent in godown A = 400.50 + 410.80
= Rs. 811.30
Question 28
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Directions: Study the following statements and choose the correct option.
Statement -1: Fraction of shaded portion of the diagram is ^.

Statement -2: Fraction of shaded portion is .

A
Both the statements are correct.

B
Both the statements are incorrect.

C
Only statement-2 is correct.

D
Only statement-1 is correct.

Solution

Only first statement is correct.
Statement-1: The total number of shaded portions is 40 and total number of portions is 64.
So, fraction would be .
After simplifying by dividing both the numerator and denominator by 8, the fraction would be ^.
Statement-2: Total number of parts is 24.

Number of shaded parts is 8.
So, fraction would be .