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Mensuration Test - 3

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Mensuration Test - 3
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Weekly Quiz Competition
  • Question 1
    1 / -0

    The ratio of the length and breadth of a rectangular field is 16 : 9 and its area is 3600 m2. Find its perimeter.

    Solution

    Let length and breadth be 16x and 9x, respectively.
    Area = 3600 m2
    ⇒ 16x × 9x = 3600
    144x2 = 3600
    ⇒  x2 = 3600/144
    x = 5
    Perimeter = 2(16 × 5 + 9 ×5) = 2(80 + 45) = 250 m

     

  • Question 2
    1 / -0

    How many metres of wallpaper 45 cm wide will be required to cover the area of a wall 15 m × 60 m?

    Solution

    Area of the wall = 15 m × 60 m = 900 m2
    Let the required length of the wallpaper be l m.
    Width of the wallpaper = 0.45 m
    Now, area of total wallpaper = Area of the wall
    l × 0.45 = 900
    ⇒  l = 2000 m

     

  • Question 3
    1 / -0

    Find the cost of fencing a rectangular field 225 m × 310 m at 45 paise per meter.

    Solution

    Perimeter of field = 2[225 m + 310 m]
    = 1070 m
    Cost of fencing per m = 0.45 Rs
    Total cost = 0.45 × 1070
    = 481.5 Rs

     

  • Question 4
    1 / -0

    What is the cost of fencing a semicircular field of radius 14 meters at the rate of Rs. 1.50 per meter?

    Solution

    Radius of semicircular field = 14 m
    Perimeter (circumference) of field = πr + 2r
    = r(π+ 2) m
    = 14(π+ 2) m
    Cost of fencing per metre = Rs. 1.50
    Total cost = 1.50 ×14 × (5.14) = Rs. 108

     

  • Question 5
    1 / -0

    The perimeter of a square is the same as the circumference of a circle of radius 12.6 cm. Find the side of the square.

    Solution

    Perimeter of square = 4 × a where a is side

    Circumference of circle with radius 12.6 cm
    = 2 × 3.14 × 12.6 = 79.2 cm

    Now perimeter of square = Circumference of circle
    4 × a = 79.2 cm
    a = 19.8 cm

     

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