Mix Test

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Mix Test - 1

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Weekly Quiz Competition

Question 1
1 / -0

The number \(3789\), when rounded off to the nearest hundreds, is:

A
\(3789\)

B
\(3790\)

C
\(3800\)

D
\(4000\)

Solution

The given number is \(3789\).
In number \(3789\), its tens digit is \(8\), which is greater than \(5\).
So, we increase the digit at hundreds place by \(1\) and replace each one of the digits at tens and ones place by \(0\) to round off the given number to nearest \(100\).
\(\therefore\) The number becomes \(3800\).
Hence, the correct option is (C).
Question 2
1 / -0

Simplify: \(21 \times(23-12)-[(-1 \times 10)+21]\)

A
\(210\)

B
\(190\)

C
\(220\)

D
\(0\)

Solution

Given,
\(21 \times(23-12)-[(-1 \times 10)+21]\)
\(= 21 \times(11)-[-10+21]\)
\(= 21 \times 11-[11]\)
\(= 231-11\)
\(= 220\)
Hence, the correct option is (C).
Question 3
1 / -0

The LCM of \(12\) and \(16\) is:

A
\(32\)

B
\(60\)

C
\(48\)

D
None of these

Solution

The LCM of \(12\) and \(16\) is:
\(\begin{array}{c|ccc}
2 & 12 & 16& \\
\hline 2 & 6 & 8 \\
\hline 2 & 3 & 4 \\
\hline 2 & 3 & 2 \\
\hline 3 & 3 & 1 \\
\hline & 1 & 1
\end{array}\)
LCM \(=2 \times 2 \times 2 \times 2 \times 3=48\)
So, the LCM of \(12\) and \(16\) is \(48\).
Hence, the correct option is (C).
Question 4
1 / -0

Simplify up to two decimal places:
\(4.38 \times 5.78+7.6\)

A
\(42.92\)

B
\(32.92\)

C
\(23.92\)

D
\(42.29\)

Solution

Given,
\(4.38 \times 5.78+7.6\)
\(= 25.3164+7.6\)
\(= 25.32+7.6\)
\(=32.92\)
Hence, the correct option is (B).
Question 5
1 / -0

Face value of \(7\) in \(3728456\):

A
\(7,00,000\)

B
\(7,000\)

C
\(7\)

D
\(70,000\)

Solution

As we know,
The face value of a digit in a number is the value of that digit itself regardless of its position in the number.
\(\therefore\) Face value of \(7\) in \(3728456\) is \(7\).
Hence, the correct option is (C).
Question 6
1 / -0

Simplify: \(32 \div 16+8(96 \div 12)-8\)

A
\(68\)

B
\(58\)

C
\(54\)

D
\(64\)

Solution

Given,
\(32 \div 16+8(96 \div 12)-8\)
\(=\frac{32}{16}+8 \times \left(\frac{96}{12}\right)-8\)
\(= 2+8 \times (8)-8\)
\(= 2+64-8\)
\(= 66-8\)
\(=58\)
Hence, the correct option is (B).
Question 7
1 / -0

Direction: What approximate value should come in the place of question mark (?) in the following question?

\(6.03 \times 36.06+\frac{131.99}{10.99}+2=?\)

A
\(180\)

B
\(250\)

C
\(130\)

D
\(230\)

Solution

Given,

\(6.03 \times 36.06+\frac{131.99}{10.99}+2=?\)

Approximating the value to the nearest integer, we get

\(6 \times 36+\frac{132}{11}+2=?\)

\(\Rightarrow 6 \times 36 +12+2=?\)

\(\Rightarrow 216+12+2=?\)

\(\therefore ?=230\)

Hence, the correct option is (D).
Question 8
1 / -0

Direction: What approximate value should come in the place of question mark (?) in the following question?

\(63.70 \times 2.3+46.40 + 3.8-23.6 =?\)

A
\(150\)

B
\(120\)

C
\(152\)

D
\(154\)

Solution

Given,

\(63.70 \times 2.3+46.40 + 3.8-23.6 =?\)

Approximating the value to the nearest integer, we get

\(64 \times 2 +46 +4-24=?\)

\(\Rightarrow 128+46 + 4-24=?\)

\(\Rightarrow 174 + 4-24=?\)

\(\Rightarrow 178-24=?\)

\(\therefore ?=154\)

Hence, the correct option is (D).
Question 9
1 / -0

Find the H.C.F. of \(26,91\) and \(117\).

A
\(11\)

B
\(13\)

C
\(7\)

D
\(9\)

Solution

Factors of \(26,91\) and \(117\):
\(26=2 \times 13 \)
\(91=7 \times 13 \)
\(117=3 \times 3 \times 13\)
Common factor \(=13\)
\(\therefore\) The HCF of the \(26,91\) and \(117\) is \(13\).
Hence, the correct option is (B).
Question 10
1 / -0

Arrange the fractions \(\frac{3}{4}, \frac{5}{12}, \frac{11}{18}, \frac{17}{24}\) in ascending order:

A
\(\frac{3}{4}, \frac{5}{12}, \frac{11}{18}, \frac{17}{24}\)

B
\(\frac{5}{12}, \frac{11}{18}, \frac{17}{24}, \frac{3}{4}\)

C
\(\frac{17}{24}, \frac{11}{18}, \frac{5}{12}, \frac{3}{4}\)

D
\(\frac{5}{12}, \frac{3}{4}, \frac{11}{18}, \frac{17}{24}\)

Solution

Given,
\(\frac{3}{4}, \frac{5}{12}, \frac{11}{18}, \frac{17}{24}\)
To make denominator of each fraction same, taking the LCM of the denominator of the given fraction.
LCM of \((4,12,18,24)=72\)
Multiplying each fraction by \(72\), we get
\(\frac{3}{4} \times 72=54\)
\(\frac{5}{12} \times 72=30\)
\(\frac{11}{18} \times 72=44\)
\(\frac{17}{24} \times 72=51\)
Arranging numbers in ascending order, we get
\(30 < 44< 51<54\)
\(\therefore\) Fractions in ascending order: \(\frac{5}{12} < \frac{11}{18} < \frac{17}{24} < \frac{3}{4}\)
Hence, the correct option is (B).

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Re-Attempt Weekly Quiz Competition

Mix Test - 1

Result

Mix Test - 1

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Rank

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SHARING IS CARING

Question 1

\(3789\)

\(3790\)

\(3800\)

\(4000\)

Solution

Question 2

\(210\)

\(190\)

\(220\)

\(0\)

Solution

Question 3

\(32\)

\(60\)

\(48\)

None of these

Solution

Question 4

\(42.92\)

\(32.92\)

\(23.92\)

\(42.29\)

Solution

Question 5

\(7,00,000\)

\(7,000\)

\(7\)

\(70,000\)

Solution

Question 6

\(68\)

\(58\)

\(54\)

\(64\)

Solution

Question 7

\(180\)

\(250\)

\(130\)

\(230\)

Solution

Question 8

\(150\)

\(120\)

\(152\)

\(154\)

Solution

Question 9

\(11\)

\(13\)

\(7\)

\(9\)

Solution

Question 10

\(\frac{3}{4}, \frac{5}{12}, \frac{11}{18}, \frac{17}{24}\)

\(\frac{5}{12}, \frac{11}{18}, \frac{17}{24}, \frac{3}{4}\)

\(\frac{17}{24}, \frac{11}{18}, \frac{5}{12}, \frac{3}{4}\)

\(\frac{5}{12}, \frac{3}{4}, \frac{11}{18}, \frac{17}{24}\)

Solution

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