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Mix Test - 3

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Weekly Quiz Competition
  • Question 1
    1 / -0

    How many whole numbers are there between \(32\) and \(52\)?

    Solution

    Whole numbers between \(32\) and \(52\) is \(19\).

    \( (52−32−1=19)\)

    \((33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51)\)

    Hence, the correct option is (A).

  • Question 2
    1 / -0

    Find the sum of \(1.2\) and \(2.3\).

    Solution

    The sum of \(1.2\) and \(2.3\):

    \(= 1.2+2.3\)

    \(=3.5\)

    Hence, the correct option is (B).

  • Question 3
    1 / -0

    Find the LCM of \(216\) and \(240\).

    Solution

    Factors of \(216=2 \times 2 \times 2 \times 3 \times 3 \times 3\)

    Factors of \(240=2 \times 2 \times 2 \times 2 \times 3 \times 5\)

    LCM \( =2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 5=2160\)

    Hence, the correct option is (A).

  • Question 4
    1 / -0

    Identify the number that when multiplied by the number \(82\), gives the same number.

    Solution

    \(1\) multiplied by the number \(82\), gives the same number.

    '\(1\)' is the only number that when multiplied to any number gives the same number.

    Hence, the correct option is (D).

  • Question 5
    1 / -0

    Find the simple interest on \(₹ 6000\) for \(1 \frac{1}{2}\) year at \(8 \%\) per annum.

    Solution
    Given,
    Principle \((P)=₹ 6000\)
    Rate \((R)=8 \%\)
    Time \((T)=1 \frac{1}{2}=\frac{3}{2}\) year
    As we know,
    Simple Interest \(=\left(\frac{P \times R \times T}{100}\right) \)
    \(=\left(\frac{6000 \times 8 \times 3}{100 \times 2}\right) \)
    \(=\frac{1440}{2} \)
    \(=₹ 720\)
    Thus, Simple Interest is ₹ \(720\).
    Hence, the correct option is (C).
  • Question 6
    1 / -0

    Ram bought a pen for Rs. \(20\) and sold it for Rs. \(25\). Find his percentage of gain.

    Solution
    Given,
    Cost price of pen \(=20\)
    Selling price of pen \(=25\)
    Net profit \(=25-20=5\)
    Profit percentage \(=\frac{\text { profit }}{\text { cost price }} \times 100\)
    \(=\frac{5}{20} \times 100\)
    \(=25 \%\)
    Hence, the correct option is (D).
  • Question 7
    1 / -0

    Example for a proper fraction is:

    Solution

    Proper fraction is a fraction in which the numerator is less than the denominator, for example \(\frac{11}{23}\).

    So, \(\frac{11}{23}\) is a proper fraction.

    Hence, the correct option is (B).

  • Question 8
    1 / -0

    Bob bought a cycle for Rs. \(3725\). After using it for few months he sold it for a loss of Rs. \(589\). Find the selling price of the cycle.

    Solution

    Given,

    Cost price of cycle \(=\) Rs. \(3725\)

    Loss \(=\) Rs. \(589\)

    As we know,

    Selling price \(=\) Cost price \(-\) loss

    Selling price of cycle \(=3725-589\)

    \(=\) Rs. \(3136\)

    Hence, the correct option is (B).

  • Question 9
    1 / -0

    Find the simple interest on \(₹ 4000\) for \(6\) years at \(1 \frac{3}{8} \%\) per annum.

    Solution
    Given,
    Principle \((P)=₹ 4000\)
    Rate \((R)=1 \frac{3}{8} \%=\frac{11}{8} \%\)
    Time \((T)=6\) years
    As we know,
    Simple Interest \(=\left(\frac{P \times R \times T}{100}\right)\)
    \(=\left(\frac{4000 \times 11 \times 6}{8 \times 100}\right)\)
    \(=\frac{2640}{8}\)
    \(=₹ 330\)
    So, the Simple Interest is ₹ \(330\).
    Hence, the correct option is (B).
  • Question 10
    1 / -0

    Find the total number of factors of \(4160\).

    Solution

    Factor of \( (4160) =2^{6} \times 5^{1} \times 13^{1} \)

    \(=(6+1)(1+1)(1+1) \)

    \(= 7 \times 2 \times 2 \)

    \(= 28\)

    Hence, the correct option is (A).

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