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Quadrilaterals Test - 6

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Quadrilaterals Test - 6
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  • Question 1
    1 / -0

    The angles of a quadrilateral, taken in order, measure x, x + 20, x + 30 and x + 50 degrees. This quadrilateral is a

    Solution

    Angles of a quadrilateral add up to 360o.

    ∴ x + (x + 20) + (x + 30) + (x + 50) = 360o
    4x + 100 = 360
    4x = 260
    x = 65o

    ∴ 1st angle = x = 65o
    2nd angle = x + 20 = 65 + 20 = 85o
    3rd angle = x + 30 = 65 + 30 = 95o
    4th angle = x + 50 = 65 + 50 = 115o

     

  • Question 2
    1 / -0

    ABCD is a quadrilateral. If AC and BD bisect each other, then ABCD is a

    Solution

    ABCD is a quadrilateral. AB = BC = CD = DA and ∠ A = ∠ B = ∠ C = ∠ D = 90°
    Then ABCD can be called A SQUARE.

     

  • Question 3
    1 / -0

    In a parallelogram ABCD, if ∠A = 60°, then ∠B, ∠C and ∠D are respectively

    Solution

    In a parallelogram ABCD, if ∠A = 60°, then ∠C = ∠A = 60

     

  • Question 4
    1 / -0

    In a parallelogram ABCD, AB = 4 cm and BC = 8 cm. Each of its diagonals is less than

    Solution

    In a parallelogram ABCD, AB = 4 cm and BC = 8 cm. Each of its diagonals is less than 12 cm because if we apply pythagorus theorem on a rectangular parallelogram, the diagonal will comes out to be 9 cm which is less than 12 cm.

     

  • Question 5
    1 / -0

    ABCD is a quadrilateral. AB = BC = CD = DA and ∠A = ∠B = ∠C = ∠D = 90°. Then ABCD is

  • Question 6
    1 / -0

    In a square ABCD, its diagonals bisect at O. Then the triangle AOB is

  • Question 7
    1 / -0

    Two parallelograms stand on equal bases and between the same parallels. The ratio of their areas is

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