Alphanumeric Series Test

Result

Alphanumeric Series Test - 1

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Question 1
1 / -0

Find the missing term in the following series:

Z1A, X2D, V6G, T21J, R88M, P445P, ?

A
N2676S

B
N2676T

C
T2670N

D
T2676N

Solution

The missing term in the series is N2676S.
Question 2
1 / -0

Find the missing term in the following series:

G4T, ?, M20P, P43N, S90L

A
J10R

B
J9R

C
R20J

D
I20J

Solution

First element: G + 3 = J, J + 3 = M, M + 3 = P, P + 3 = S
Second element: 4 × 2 + 1 = 9, 9 × 2 + 2 = 20, 20 × 2 + 3 = 43, 43 × 2 + 4 = 90
Third element: T - 2 = R, R - 2 = P, P - 2 = N, N - 2 = L
So, the missing term is J9R.
Question 3
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Directions: In the following question, a letter-number series is given with two terms missing represented by the question marks (?). Choose the missing terms from the given alternatives.

D – 4, F – 6, H – 8, J – 10, ?, ?

A
K – 12, M – 13

B
L – 12, M – 14

C
L – 12, N – 14

D
K – 12, M – 14

Solution
Question 4
1 / -0

Directions: In the following question, a letter-number series is given with one term missing as shown by the question mark (?). Choose the missing term out of the given alternatives.

2Z5, 7Y7, 14X9, 23W11, 34V13, ?

A
27U24

B
45U15

C
47U15

D
47V14

Solution
Question 5
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Directions: In the following question, a letter-number series is given with one term missing as shown by the question mark (?). Choose the missing term out of the given alternatives.

I2Z, J4X, K7V, ?, M16R, N22P

A
I11T

B
L11S

C
L12T

D
L11T

Solution

First series is as follows:
I, J, K, L, M, N
Second series is as follows:
2 + 2 = 4
4 + 3 = 7
7 + 4 = 11
11 + 5 = 16
16 + 6 = 22
Third series is as follows:
Z - 2 = X
X - 2 = V
V - 2 = T
T - 2 = R
R - 2 = P
So, L11T is the correct answer.
Question 6
1 / -0

Directions: In the following question, a letter-number series is given with one term missing as shown by the question mark (?). Choose the missing term out of the given alternatives.

2A11, 4D13, 12G17, ?

A
36I19

B
36I20

C
48J21

D
48J23

Solution

The first numbers in the terms follow the pattern: x2, x3, x4.
The middle letter of each term is moved three steps forward to obtain the corresponding letter of the next term.
The last numbers follow the pattern: +2, +4, +6.

So, the next term is:
(12 x 4)(G + 3)(17 + 6) = 48J23
Question 7
1 / -0

Directions: In the following question, a letter-number series is given with one term missing as shown by the question mark (?). Choose the missing term out of the given alternatives.

C4X, F9U, I16R, ?

A
K25P

B
L25P

C
L25O

D
L27P

Solution

Pattern I: C + 3 = F, F + 3 = I, I + 3 = L
Therefore, the series is C, F, I, L.

Pattern II: (2)²,(3)²,(4)²,(5)²Pattern III: X - 3 = U, U - 3 = R, R - 3 = O
Question 8
1 / -0

Directions: In the following question, a letter-number series is given with one term missing as shown by the question mark (?). Choose the missing term out of the given alternatives.

3F, 6G, 11I, 18L, ?

A
21O

B
25N

C
25P

D
27P

Solution

The letters in the first, second, third and fourth terms are respectively moved one, two, three and four steps forward to obtain the letter in the subsequent terms. The numbers follow the pattern: +3, +5, +7, +9.

So, the next term is:
(18 + 9)(L + 4) = 27P
Question 9
1 / -0

Directions: In the following question, a letter-number series is given with one term missing as shown by the question mark (?). Choose the missing term out of the given alternatives.

KM5, IP8, GS11, EV14, ?

A
BX17

B
BY17

C
CY17

D
CY18

Solution

The first letter of each term is moved two steps backwards and the second letter is moved three steps forward to obtain the corresponding letters of the next term.
The number in each term is 3 more than that in the preceding term.
Question 10
1 / -0

Directions: In the following question, a letter-number series is given with one term missing as shown by the question mark (?). Choose the missing term out of the given alternatives.

W – 144, ?, S – 100, Q – 81, O – 64

A
U – 121

B
U – 122

C
V – 121

D
V – 128

Solution