MAT (Stage-2) Mock Test

Result

MAT (Stage-2) Mock Test - 22

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Weekly Quiz Competition

Question 1
1 / -0

Complete the following series:

F, K, P, U, Z, E, ___

A
K

B
J

C
I

D
L

Solution

F + 5 = K
K + 5 = P
P + 5 = U
U + 5 = Z
Z + 5 = E
E + 5 = J

The next term is 'J'.
Question 2
1 / -0

In the following question, a letter-number series is given with one term missing as shown by (?). Choose the missing term out of the given alternatives.

3F, 6G, 11I, 18L, ?

A
21O

B
25N

C
25P

D
27P

Solution

3 + 3 = 6, 6 + 5 = 11, 11 + 7 = 18, 18 + 9 = 27
F + 1 = G, G + 2 = I, I + 3 = L, L + 4 = P
Question 3
1 / -0

In the following question, a letter-number series is given with one term missing as shown by (?). Choose the missing term out of the given alternatives.

C4X, F9U, I16R, ?

A
K25P

B
L25P

C
L25O

D
L27P

Solution

C + 3 = F, F + 3 = I, I + 3 = O
(2)² = 4, (3)²= 9, (4)²= 16, (5)²= 25
X - 3 = U, U - 3 = R, R - 3 = O, O - 3 = L
Question 4
1 / -0

In the following question, a letter-number series is given with one term missing as shown by (?). Choose the missing term out of the given alternatives.

2A11, 4D13, 12G17, ?

A
36I19

B
36I20

C
48J21

D
48J23

Solution

2 X 2 = 4, 4 X 3 = 12, 12 X 4 = 48
A + 3 = D, D + 3 = G, G + 3 = J
11 + 2 = 13, 13 + 4 = 17, 17 + 6 = 23
Question 5
1 / -0

In the following question, a letter-number series is given with one term missing as shown by (?). Choose the missing term out of the given alternatives.

J2Z, K4X, I7V, ?, H16R, M22P

A
I11T

B
L11S

C
L12T

D
L11T

Solution

The first letters in odd numbered terms form the series J, I, H and in even numbered terms from the series K, L, M.
The sequence followed by the numbers is +2, +3, +4, +5, +6.
The third element (letter) of each term is moved two steps backward to obtain the third element of the next term.
Question 6
1 / -0

In the following question, a letter-number series is given with one term missing as shown by (?). Choose the missing term out of the given alternatives.

2Z5, 7Y7, 14X9, 23W11, 34V13, ?

A
27U24

B
45U15

C
47U15

D
47V14

Solution

2 + 5 = 7, 7 + 7 = 14, 14 + 9 = 23, 23 + 11 = 34, 34 + 13 = 47
Z - 1 = Y, Y - 1 = X, X - 1 = W, W - 1 = V, V - 1 = U
5 + 2 = 7, 7 + 2 = 9, 9 + 2 = 11, 11 + 2 = 13, 13 + 2 = 15
Question 7
1 / -0

The pendulum of a clock takes 7 seconds to strike 4 times at 4 o'clock. How much time will it take to strike 11 times at 11 o'clock? It can be assumed that the time elapsed between two successive strikes is equal to the time period of 1 single strike.

A
19.25 seconds

B
21 seconds

C
22 seconds

D
Cannot be determined

Solution

When the clock strikes 4 times at 4 o'clock, there are 4 strike periods and 3 silent periods (1 silent period between 2 successive strikes), making a total of 7 periods. So, for 7 periods, it takes a time of 7 seconds. This implies each period lasts 1 second. When the clock strikes 11 times at 11 o'clock, there are 11 strike periods and 10 silent periods in-between, making a total of 21 periods.
Thus, total time = 21 seconds
Question 8
1 / -0

In a certain code, POETRY is written as QONDSQX and OVER is written as PNUDQ. How is MORE written in that language?

A
LNNQD

B
NNNQD

C
NLNQD

D
NLPQD

Solution

The first letter of the word is replaced by a set of two letters - one following it and the other preceding it - in the code. The remaining letters are coded by its preceding letter in the English alphabet.

M + 1 ⇒ N
M - 1 ⇒ L
O - 1 ⇒ N
R - 1 ⇒ Q
E - 1 ⇒ D
Question 9
1 / -0

If BE QUICK is coded as ZC OSGAI, then the code of the last letter of the third word in the sentence I LOVE MY COUNTRY is

A
A

B
T

C
U

D
W

Solution

Each letter in the given message is moved two steps backward to obtain the corresponding letter of the code.
Y will be coded as W.
Question 10
1 / -0

If in a certain code, TWINKLE is written as SVHOJKD, then how would FILTERS be written in the same code?

A
EHKSDQR

B
EHKUDQR

C
EGKUDQR

D
GJMSFST

Solution

Each letter in the word, except the middle letter, is moved one step backward, while the middle letter is moved one step forward to obtain the corresponding letters of the code.
F - 1 = E
I - 1 = H
L - 1 = K
T + 1 = U
E - 1 = D
R - 1 = Q
S - 1 = R
Question 11
1 / -0

In a certain code, ROAD is written as URDG. How will SWAN be written in that code?

A
VXDQ

B
VZDQ

C
VZCP

D
UXDQ

Solution

Each letter in the word is moved three steps forward to obtain the corresponding letter of the code.
S + 3 = V
W + 3 = Z
A + 3 = D
N + 3 = Q

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Re-Attempt Weekly Quiz Competition

MAT (Stage-2) Mock Test - 22

Result

MAT (Stage-2) Mock Test - 22

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SHARING IS CARING

Question 1

K

J

I

L

Solution

Question 2

21O

25N

25P

27P

Solution

Question 3

K25P

L25P

L25O

L27P

Solution

Question 4

36I19

36I20

48J21

48J23

Solution

Question 5

I11T

L11S

L12T

L11T

Solution

Question 6

27U24

45U15

47U15

47V14

Solution

Question 7

19.25 seconds

21 seconds

22 seconds

Cannot be determined

Solution

Question 8

LNNQD

NNNQD

NLNQD

NLPQD

Solution

Question 9

A

T

U

W

Solution

Question 10

EHKSDQR

EHKUDQR

EGKUDQR

GJMSFST

Solution

Question 11

VXDQ

VZDQ

VZCP

UXDQ

Solution

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