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MAT (Stage-1) Mock Test - 23

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MAT (Stage-1) Mock Test - 23
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which of the following will replace the question mark (?) in the grid given below?

    81 121 20
    36 ? 14
    49 64 15
    Solution

    (√21 + √81) = 20; (√49 + √64) = 15 (Row-wise)
    The missing number is (√36 + √x) = 14
    So, x = 64

     

  • Question 2
    1 / -0

    In a town, 65% of the people watch news on television, 40% read newspaper and 25% read newspaper and watch news on television also. What percentage of the people neither watch news on television nor read newspaper?

    Solution

    n(a + b) = n(a) + n(b) - n(a × b), here + and × represents OR and AND

    So, n(a + b) = 65 + 40 - 25 = 80

    So, 20% people neither watch TV nor read newspaper.

     

  • Question 3
    1 / -0

    Five years ago, Vinay's age was one-third the age of Vikram's age at that time and now Vinay's age is 17 years. What is the present age of Vikram?

    Solution

    Vinay's present age = 17 years
     Five years ago, Vinay's age = (17 - 5) years = 12 years
    Five years ago, Vikram's age = (12 × 3) years = 36 years
    Hence, Vikram's present age = (36 + 5) years = 41 years

     

  • Question 4
    1 / -0

    The age of Arvind's father is 4 times his age. If 5 years ago, his father's age was 7 times the age of his son, what is the age of Arvind's father at present?

    Solution

    The present age of Arvind and his father is x and 4x, respectively.
    Five years ago, the age of Arvind and his father become (x - 5) and (4x - 5), respectively.
    According to the question,
    ∴ 4x - 5 = 7(x - 5)
    4x - 5 = 7x - 35
    7x - 4x = 35 - 5
    3x = 30
    x = 10
    Father's present age = 4x = 4 × 10 = 40 years

     

  • Question 5
    1 / -0

    A number consists of two digits, whose sum is 11. If 27 is added to the number, then the digits change their places. What is the number?

    Solution

    Let x be in tens place and y in units place.
    Therefore, the number is 10x + y.
    Given, x + y = 11
    Also, on adding 27 to the number, the new number becomes 10y + x.
    => 10x + y + 27 = 10y + x
    => x - y = - 3
    Solving these two equations,
    x = 4, y = 7
    Hence, the number is 47.

     

  • Question 6
    1 / -0

    A bag contains 25 paise, 10 paise and 5 paise coins in the ratio 1 : 2 : 3. If the total value of the coins is Rs. 36, find the number of 25 paise coins.

    Solution

    Let x be the number of 25 paise coins.
    ∴ Number of 10 paise coins = 2x
    ∴ Number of 5 paise coins = 3x
    Total value of the coins = 25x + 10 × 2x + 5 × 3x = 3600 paise
    ⇒ 25x + 20x + 15x = 3600
    ⇒ x = 3600/60 = 60
    ∴ Number of coins of 25 paise = 60

     

  • Question 7
    1 / -0

    The marked price of a jacket is $1050. A shopkeeper earns a profit of 25% even after offering a discount of 10%. At what price does he purchase the jacket himself?

    Solution

    MP of jacket = $1050
    SP after 10% discount = 1050 - 10% of 1050 = $945
    Let CP of jacket be x.
    According to the question:
    1.25x = 945
    x = 945 × 100/125 = $756

     

  • Question 8
    1 / -0

    A man sells an article at a gain of 10%. If he had bought it at 10% less and sold it for Rs. 132 less, he would have still gained 10%. The cost price of the article is

    Solution

    SP = 1.1 CP
    New cost price = 0.9 CP
    New selling price = SP - 132
    According to the given condition,
    SP - 132 = 1.1(0.9 CP)
    1.1 CP - 132 = 0.99 CP
    0.11 CP = 132
    CP = Rs. 1200

     

  • Question 9
    1 / -0

    A can do a piece of work in 30 days while B can do it in 40 days. In how many days can A and B working together do it?

    Solution

    A's one day work = 1/30
    B's one day work = 1/40
    One day work of both A and B = 1/30+1/40
    = 4+3/120 = 7/120
    Hence, they together will complete the work in 120/7 days.

     

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