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MAT (Stage-1) Mock Test - 73

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MAT (Stage-1) Mock Test - 73
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Weekly Quiz Competition
  • Question 1
    1 / -0

    In the following question, a figure marked 'X' is followed by figures (a), (b), (c) and (d) which show the possible water images of figure 'X'. Choose one out of these four figures that shows the correct water image of figure 'X'.

    Solution

     

  • Question 2
    1 / -0

    In the following question, four alternatives are given which follow a word given below. You have to select one alternative that exactly matches with the mirror image of the word in question.

    Solution

     

  • Question 3
    1 / -0

    In the following question, choose the correct mirror image from alternatives (a), (b), (c), (d) of the figure (A).

    Solution

     

  • Question 4
    1 / -0

    In the following question, choose the correct mirror image from alternatives (a), (b), (c), (d) of the figure (A).

    Solution

     

  • Question 5
    1 / -0

    In the following question, choose the correct mirror image from alternatives (a), (b), (c), (d) of the figure (A).

    Solution

     

  • Question 6
    1 / -0

    Consider the following alphametic puzzle in which E = 5, M = 2 and N = 3.

    What is the value of 'R'?

    Solution

    Here, E = 5 and N = 3 (given)
    5 + R should be 13 to get N = 3.
    As 5 + R = 13, R = 8

     

  • Question 7
    1 / -0

    The question is based on the multiplication given below, where each letter represents a distinct single-digit number and no two numbers are represented by the same letter.

    What is the value of D?

    Solution

    B + E = B. So, E = 0
    So, on multiplying D and B, we should get a 2-digit number, with unit place (E) as 0. This is possible if D = 5 and B = 2.
    (Note: It is not possible for D = 2 and B = 5, since then C + F = D will make both C and F = 1, which is not allowed as per the rules of the question.)
    Since on multiplying D with C we get D, C should be equal to 1.
    Further, we have C + F = D = 5
    So, F = 5 - 1 = 4
    Further, F + G = 10 (since unit place E = 0)
    So, G = 10 - 4 = 6
    Also, since F = 4 and C = 1, we get first line solution FCED = 4105. This means D × A = 40 + 1 (carryover) = 41
    i.e. 5A + 1 = 41
    So, A = 8
    So, we have A = 8, B = 2, C = 1, D = 5, E = 0, F = 4 and G = 6
    So, D = 5

     

  • Question 8
    1 / -0

    The question is based on the multiplication given below, where each letter represents a distinct single-digit number and no two numbers are represented by the same letter.

    What is the value of B × E?

    Solution

    B + E = B. So, E = 0
    So, on multiplying D and B, we should get a 2-digit number, with unit place (E) as 0. This is possible if D = 5 and B = 2.
    Since on multiplying D with C we get D, C should be equal to 1.
    (Note: It is not possible for D = 2 and B = 5, since then C + F = D will make both C and F = 1, which is not allowed as per the rules of the question.)
    So, BE = 2 × 0 = 0

     

  • Question 9
    1 / -0

    Two positions of a dice are given. Which of the following numbers would be at the top when 2 is at the bottom?

    Solution

    Number 3 appears in the same position both times.
    The pattern of numbers is as given below.
    From first orientation, write the numbers in clockwise direction.
    3 - 5 - 2
    From second orientation, write the numbers in clockwise direction.
    3 - 1 - 6
    Hence, 2 is opposite to number 6 and 5 is opposite to number 1.

     

  • Question 10
    1 / -0

    A cube of side 10 cm is coloured red, with a 2 cm wide green strip along all the sides on all the faces. The cube is cut into 125 smaller cubes of equal sizes. How many cubes have at least two green faces each?

    Solution

    There are 12 cubes in each of the layers 1 and 5 and 4 cubes in each of the layers 2, 3 and 4 which have two faces coloured green. Also, there are 4 cubes in each of the layers 1 and 5 which have three faces coloured green.

    3 faces coloured cubes = 8
    2 faces coloured cubes = 24 + 12 = 36
    Total cubes = 44

     

  • Question 11
    1 / -0

    In the following question, four number pairs are given. Three of them are alike in a certain way and one is different. Find the odd one out from the alternatives.

    Solution

    Second number is 3/2 more than first number.

     

  • Question 12
    1 / -0

    Find the odd one out.

    Solution

    Except calcium, all the others are energy sources.

     

  • Question 13
    1 / -0

    In the following question, four groups of letters are given. One of these is different from the others in some way. Find the odd one out.

    Solution

    B(2): 22 = 4 = D
    E(5): 52 = 25 = Y
    D(4): 42 = 16 = P
    C(3): 32 = 9 = I ≠ J

     

  • Question 14
    1 / -0

    In the following question, four groups of letters are given. One of these is different from the others in some way. Find the one that is different from the others.

    Solution

     

  • Question 15
    1 / -0

    In the following question, four groups of letters are given. One of these is different from the others in some way. Find the one that is different from the others.

    Solution

    Going by options:
    1. NO = N + 1 = O
    2. MP = M + 3 = P
    3. UX = U + 3 = X
    4. ZC = Z + 3 = C

     

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