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MAT (Stage-1) Mock Test - 89

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MAT (Stage-1) Mock Test - 89
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  • Question 1
    1 / -0

    Directions For Questions

    In the question given below, there is a group of letters followed by combinations of digits/symbols lettered (1), (2), (3) and (4). You have to find out which of the combinations correctly represents the group of letters based on the coding system and mark the letter of that combination as your answer.

    Letter: E I U A P S B X H W T
    Digit/Symbol Code: $ 9 # @ 4 3 % 1 = 7 6

    Conditions:
    (i) If both the first and the last letters are consonants, then all the vowels are to be coded as the code of E.
    (ii) If both the first and the last letters are vowels, then both are to be coded by &.
    (iii) If the first letter is a vowel and the last letter is a consonant, then their codes are to be interchanged.

    ...view full instructions

    PTUWT

    Solution

    Both first and last letters are consonants, so it should follow condition (i).
    The code of PTUWT is 46$76.

     

  • Question 2
    1 / -0

    Directions For Questions

    In the question given below, there is a group of letters followed by combinations of digits/symbols lettered (1), (2), (3) and (4). You have to find out which of the combinations correctly represents the group of letters based on the coding system and mark the letter of that combination as your answer.

    Letter: E I U A P S B X H W T
    Digit/Symbol Code: $ 9 # @ 4 3 % 1 = 7 6

    Conditions:
    (i) If both the first and the last letters are consonants, then all the vowels are to be coded as the code of E.
    (ii) If both the first and the last letters are vowels, then both are to be coded by &.
    (iii) If the first letter is a vowel and the last letter is a consonant, then their codes are to be interchanged.

    ...view full instructions

    STPXW

    Solution

    Both first and last letters are consonants, so it should follow condition (i).
    The code of STPXW is 36417.

     

  • Question 3
    1 / -0

    Directions For Questions

    In the question given below, there is a group of letters followed by combinations of digits/symbols lettered (1), (2), (3) and (4). You have to find out which of the combinations correctly represents the group of letters based on the coding system and mark the letter of that combination as your answer.

    Letter: E I U A P S B X H W T
    Digit/Symbol Code: $ 9 # @ 4 3 % 1 = 7 6

    Conditions:
    (i) If both the first and the last letters are consonants, then all the vowels are to be coded as the code of E.
    (ii) If both the first and the last letters are vowels, then both are to be coded by &.
    (iii) If the first letter is a vowel and the last letter is a consonant, then their codes are to be interchanged.

    ...view full instructions

    ESITU

    Solution

    The coding is correct because it follows the condition (ii) as both the first and the second letters are vowels and both vowels should be coded as &.

     

  • Question 4
    1 / -0

    Directions For Questions

    In the question given below, there is a group of letters followed by combinations of digits/symbols lettered (1), (2), (3) and (4). You have to find out which of the combinations correctly represents the group of letters based on the coding system and mark the letter of that combination as your answer.

    Letter: E I U A P S B X H W T
    Digit/Symbol Code: $ 9 # @ 4 3 % 1 = 7 6

    Conditions:
    (i) If both the first and the last letters are consonants, then all the vowels are to be coded as the code of E.
    (ii) If both the first and the last letters are vowels, then both are to be coded by &.
    (iii) If the first letter is a vowel and the last letter is a consonant, then their codes are to be interchanged.

    ...view full instructions

    ASBWT

    Solution

    The coding is correct because it follows the condition (iii) as first letter is a vowel and last letter is a consonant.

     

  • Question 5
    1 / -0

    Pooja walked 35 m from a certain point towards south, then she turned left and walked 17 m, and finally, she turned left again and walked 35 m. How far was she from the starting point?

    Solution

    According to the directions given in the question, the following diagram is obtained:

    Pooja was 17 m far from her initial position.

     

  • Question 6
    1 / -0

    Ranjan goes 5 km towards north from a fixed point. Then, he goes 3 km after turning to his right. After that, he goes another 5 km turning to his right. Finally, he goes 4 km after turning to his left. How far and in which direction is he now with respect to the starting point?

    Solution

    The diagrammatic representation of the same is given above:
    Required distance = SD = SC + CD = 3 km + 4 km = 7 km

     

     

  • Question 7
    1 / -0

    Which of the following numbers would replace the question mark (?) in the given figure?

    40 9 41
    71 11 50
    18 ? 18
    Solution

    Row 1: 40 + 41 = 81 and √81 = 9

    Row 2: 71 + 50 = 121 and √121 = 11

    Row 3: 18 + 18 = 36 and √36 = 6

     

  • Question 8
    1 / -0

    Find the missing term out of the options given below after studying the relationship among the other given figures.

    Solution

    The pattern followed here is

     

  • Question 9
    1 / -0

    Find the missing term out of the options given below after studying the relationship among the other given figures.

    Solution

    Middle number is obtained as follows.
    9 + 12 + 11 = 32, 32 ÷ 4 = 8
    8 + 13 + 15 = 36, 36 ÷ 4 = 9
    16 + 18 + 14 = 48, 48 ÷ 4 = 12

     

  • Question 10
    1 / -0

    The sum of the diameters of two circles is 35 cm and the difference of their circumferences is 22 cm. The area of the smaller circle will be

    Solution

     

  • Question 11
    1 / -0

    The average score of a cricketer in a certain number of innings is 15. When he scores zero in the next innings, his average drops to 13.5. How many innings have been played by him, including the last one?

    Solution

    Let the number of innings be x.
    Total runs scored by the cricketer = 15x
    New number of innings = x + 1
    Also, new average = 13.5

    15x = 13.5(x + 1)
    15x = 13.5x + 13.5
    15x - 13.5x = 13.5
    1.5x = 13.5

    Number of innings played, including the last one = 9 + 1 = 10

     

  • Question 12
    1 / -0

    What is the average speed of a cyclist who covers first, second and third kilometres with the speeds of 20 km/hr, 16 km/hr and 12 km/hr, respectively?

    Solution

    = 15.32 km/hr

     

  • Question 13
    1 / -0

    The ratio of milk and water in a mixture is 3 : 2. If 10 litres of water is added to it, the ratio gets reversed. What is the amount of the total mixture now?

    Solution

    Assume the quantities of milk and water to be 3k litres and 2k litres, respectively.
    If 10 litres of water is added, the ratio will be

    ⇒ k = 4
    So, amount of the mixture = [3k + (2k + 10)] litres = 30 litres.

     

  • Question 14
    1 / -0

    The ratio of salaries of two employees is 2 : 5. Their expenses are in the ratio 1 : 3. What is the income of the second employee (in rupees) if the savings of both of them is Rs. 50?

    Solution

    Let Rs. 2x be first employee's income.
    And Rs. 5x be second employee's income. So,


    6x - 150 = 5x - 50
    x = 100
    Income of the second employee = Rs. 500

     

     

  • Question 15
    1 / -0

    The ratio of the number of employees of a company in the first year and that in the second year is 3 : 2. The ratio of the salary of the each employee in the given two years is 4 : 5. So the company saves Rs. 12,000. Find the first year expenditure of the company.

    Solution

    Employee ratio in the first and second year = 3 : 2
    Salary ratio in the first and second year = 4 : 5
    Total expenditure of the company in the first and second year = 3 × 4 : 2 × 5 = 12 : 10
    So total expenditure is reduced by = 12 - 10 = 2
    2 unit = Rs. 12,000

    1 unit = Rs.12,000 / 2  = 6000
    So, expenditure of the company in the first year = 12 × 6000 = Rs. 72,000

     

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