SAT (Stage-1) Mock Test

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SAT (Stage-1) Mock Test - 23

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Weekly Quiz Competition

Question 1
1 / -0

The process of meiosis is responsible for the formation of haploid germ cells. In females, this process occurs in:

A
uterus

B
fallopian tube

C
ovary

D
cervix

Solution

Meiosis is actually a type of cell division that occurs in the testes of males and in the ovaries of females. Meiosis leads to the formation of cells bearing half the normal number of chromosomes. The process is also referred to as spermatogenesis in males and oogenesis in females.
Question 2
1 / -0

A disc-shaped organ that acts as a connecting link between a mother's blood and foetal blood is:

A
umbilical cord

B
placenta

C
fallopian tube

D
amniotic fluid

Solution

An embryo gets nutrition from the mother's blood with the help of a special tissue called placenta through the umbilical cord. This is a disc which lies in the uterine wall and provides a large surface area for glucose and oxygen to pass from the mother to the embryo for its development. Also, it helps in the removal of waste material from the embryo into the mother's blood. So, the placenta acts as a connecting link between a mother's blood and foetal blood.
Question 3
1 / -0

Your friend named Gaurav lives in Himachal Pradesh. He told you that many of his fellow villagers had developed a visible swelling in the neck. People in many other villages have also been affected in a similar way. The most probable reason is:

A
fluorine deficiency

B
sodium deficiency

C
iodine deficiency

D
potassium deficiency

Solution

Hilly regions have soil deficient in iodine leading to insufficient quantity of iodine in food. This causes goitre, which results in swelling of neck.
Question 4
1 / -0

Which element is essential part of the enzyme nitrogenase required during nitrogen fixation:

A
Magnesium

B
Iron

C
Molybdenum

D
Sulphur

Solution

Molybdenum is an integral part of enzyme nitrogenase, which is responsible for biological nitrogen fixation.
Question 5
1 / -0

Consider the following statements:

(1) Root hairs are specialized for the uptake of nutrients from the soil.
(2) Presence of gas bubbles in xylem do not affect the flow of water in the xylem vessels.
(3) Evaporation of water molecules from a plant's surface helps in upward movement of water.

Which of the statements given above are correct?

A
Only 1 and 2

B
Only 2 and 3

C
Only 1 and 3

D
1, 2 and 3

Solution

Root cells create a difference in ionic concentration between roots and soil.Root hairs are essential for uptake of nutrients from the soil.
Gas bubbles in the xylem can interrupt the flow of water in the plant, so they must be reduced through small perforations between vessel elements.
Question 6
1 / -0

In vegetative propagation, new plants grow from different parts of the parent plant. Which part of a plant does not take part in vegetative propagation?

A
Root

B
Stem

C
Leaf

D
Flower

Solution

Vegetative propagation means formation of new plants from vegetative parts. Flower is the sexual reproductive organ.
Question 7
1 / -0

Four farmers A, B, C and D adopt different farming practices. In which of the following cases will there be maximum benefits?

A
Farmer A uses high quality seeds, but neither uses fertilisers nor adopts irrigation practices.

B
Farmer B uses ordinary seeds, adopts irrigation and uses fertilisers only.

C
Farmer C uses high quality seeds, adopts irrigation, uses fertilisers and takes crop protection measures.

D
Farmer D uses high quality seeds, adopts irrigation and uses fertilisers, but does not take crop protection measures.

Solution

Farmer C will have the maximum benefits.The reason is that he adopts all necessary measures required for good yield. Example: high quality seeds, adopts irrigation, uses fertilisers and takes crop protection measures.
Question 8
1 / -0

Which of the following statements is/are false?

a. In the asexual reproduction method, certain body cells of the parent organism undergo repeated mitotic cell divisions to form two or more new organisms of the same kind.
b. Humans, frogs, hens, etc. reproduce by the method of sexual reproduction.
c. In binary fission, the parent organism splits to form many new organisms at the same time.

A
Only a

B
Both a and b

C
Only c

D
Both b and c

Solution

Statements a and b are correct. Statement c is incorrect as in binary fission the parent organism splits into two daughter cells and not multiple daughter cells.
Question 9
1 / -0

______ use(s) holozoic mode of nutrition.

A
Roundworms

B
Tapeworms

C
Plasmodium

D
Amoeba

Solution

Nutrition in amoeba is holozoic. Thus, solid food particles are ingested which are then acted upon by enzymes and digested. It is an omnivore, feeding on both plants and animals.
Question 10
1 / -0

There are various methods of preventing unwanted pregnancy. One of them is surgical method. This method of preventing fertilisation in females involves tying up of the

A
ovary

B
cervix

C
uterus

D
fallopian tube

Solution

As fertilisation between sperm and ovum takes place in the fallopian tube, the best way to prevent pregnancy is to cut the two slender tubes (fallopian tubes) and burn, clip or bind the cut ends. Thus, tube ligation prevents pregnancy from occurring.
Question 11
1 / -0

Ramkali saved Rs. 5 in the first week of a year and then increased her weekly savings by Rs. 1.75. If in the n^th week, her savings became Rs. 20.75, find the value of n.

A
8

B
9

C
10

D
11

Solution

Arithmetic progression is:
5 , 6.75, …, 20.75
a = 5, d = 1.75, L = 20.75
To find n:
a + (n - 1)d = 20.75
5 + (n - 1)1.75 = 20.75
(n - 1)1.75 = 15.75
n - 1 = 9
n = 10
Question 12
1 / -0

Find the remainder when 7²¹ + 7²² + 7²³ + 7²⁴ is divided by 25.

A
0

B
2

C
4

D
6

Solution

7²¹+ 7²²+ 7²³ + 7²⁴is divided by 25, i.e.

7²¹(7⁰ + 7¹ + 7² + 7³)

= 7²¹(1 + 7 + 49 + 343)

= 7²¹(400)

i.e. when 7²¹(400) is divided by 25, remainder = 0 (as 400 is divisible by 25)
Question 13
1 / -0

HCF of three numbers is 12. If they are in the ratio 1 : 2 : 3, then the numbers are

A
12, 24, 36

B
24, 48, 72

C
12, 24, 72

D
24, 48, 36

Solution

Let the numbers be a, 2a and 3a. Then, their HCF is a.
∴ a = 12 (Given)
∴The numbers are 12, 24 and 36.

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SAT (Stage-1) Mock Test - 23

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SAT (Stage-1) Mock Test - 23

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SHARING IS CARING

Question 1

uterus

fallopian tube

ovary

cervix

Solution

Question 2

umbilical cord

placenta

fallopian tube

amniotic fluid

Solution

Question 3

fluorine deficiency

sodium deficiency

iodine deficiency

potassium deficiency

Solution

Question 4

Magnesium

Iron

Molybdenum

Sulphur

Solution

Question 5

Only 1 and 2

Only 2 and 3

Only 1 and 3

1, 2 and 3

Solution

Question 6

Root

Stem

Leaf

Flower

Solution

Question 7

Farmer A uses high quality seeds, but neither uses fertilisers nor adopts irrigation practices.

Farmer B uses ordinary seeds, adopts irrigation and uses fertilisers only.

Farmer C uses high quality seeds, adopts irrigation, uses fertilisers and takes crop protection measures.

Farmer D uses high quality seeds, adopts irrigation and uses fertilisers, but does not take crop protection measures.

Solution

Question 8

Only a

Both a and b

Only c

Both b and c

Solution

Question 9

Roundworms

Tapeworms

Plasmodium

Amoeba

Solution

Question 10

ovary

cervix

uterus

fallopian tube

Solution

Question 11

8

9

10

11

Solution

Question 12

0

2

4

6

Solution