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SAT (Stage-1) Mock Test - 24

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SAT (Stage-1) Mock Test - 24
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  • Question 1
    1 / -0

    The salary of B is 10% more than the salary of A, the salary of C is 10% more than the salary of B, and the salary of D is 10% more than the salary of C. The total salary of A and D is Rs. 2100 more than that of B and C. What is the salary of B?

    Solution

    Let salary of A be x.
    Then:
    Salary of B = 1.1x
    Salary of C = 1.21x
    Salary of D = 1.331x
    A + D = 2.331x
    B + C = 2.31x

    According to the question:
    (A + D) - (B + C) = 2100
    0.021x = 2100
    x = 1,00,000
    Therefore, salary of B is Rs. 1,10,000.

     

  • Question 2
    1 / -0

    On dividing x4 + 2x2 - 3x + 7 by a polynomial g(x), the quotient and the remainder were x2 + 5 and -3x + 22, respectively. The polynomial g(x) was

    Solution

    x4 + 2x2 - 3x + 7 = (x2 + 5)g(x) - 3x + 22
    Let g(x) = x2 + ax + b
    Thus, x4 + 2x2 - 3x + 7 = (x2 + 5)(x2 + ax + b) - 3x + 22
    Or, x+ 2x2 - 3x + 7 = x4 + ax+ bx2 + 5x2 + 5ax + 5b - 3x + 22
    Or, x4 + 2x2 - 3x + 7 = x4 + ax3 + x2(b + 5) + x(5a - 3) + 5b + 22
    On comparing coefficients, we get
    a = 0, b + 5 = 2 or b = -3
    Thus, g(x) = x2 - 3

     

  • Question 3
    1 / -0

    A tradesman marks an article at a price which would give him a profit of 20% on the cost price. To the favoured customers, he makes a deduction of 5% from the marked price. What actual profit does he receive from the sale of an article to a favoured customer for which the latter pays him $28.50?

    Solution

    Let the CP of the article be $x.
    MP = x + 20% of x = $1.2x
    When a discount is given on this MP,
    SP of the article = (95/100) × 1.2x = $1.14x
    But 1.14x = 28.50
    So, x = 25
    CP of the article = $25
    SP = $28.50
    Profit = $3.50

     

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