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SAT (Stage-1) Mock Test - 30

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SAT (Stage-1) Mock Test - 30
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Organisms like jellyfish, viperfish, tube worms and sea cucumbers are found in which of the following zones?

    Solution

    Hadopelagic zone extends from 6,000 m (19,686 feet) to the bottom of the deepest parts of the ocean. Invertebrates such as starfish, jellyfish, viperfish, tube worms and sea cucumbers thrive at these depths.

     

  • Question 2
    1 / -0

    Which of the following statements is/are false?

    a. The fusion of a sperm with an egg to form a zygote during sexual reproduction is called fertilisation.
    b. The ovum has a head, a middle piece and a tail.
    c. All multicellular animals start their life from a single cell called zygote.

    Solution

    Statement b is false . Ovum does not have a head, middle piece and tail. This is the structure of the sperm.

     

  • Question 3
    1 / -0

    Five stimuli give five types of tropism. Which of the following is the stimulus in the process of thigmotropism?

    Solution

    This is the correct option. The stimulus in the process of thigmotropism is touch.

     

  • Question 4
    1 / -0

    The undigested and unabsorbed food from small intestine enters into organ B. The organ B absorbs most of the water from the undigested waste food material making it semi-solid. This semisolid waste is stored in part C of organ B for some time. It is passed out from the body through part D in the form of feces.

    What are B, C and D respectively in the above passage?

    Solution

    The organ B, C and D in the above passage are large intestine, rectum and anus, respectively.

     

  • Question 5
    1 / -0

    Which of the following parts occur(s) in the reproductive system of flowering plants as well as that of human females?

    Solution

    This is the correct option. Ovary occurs in the reproductive system of flowering plants as well as that of females.

     

  • Question 6
    1 / -0

    If p(x) = x– k and x = 7 is a zero of p(x), then find the value of k.

    Solution

    Zero of a polynomial p(x) is the value c such that p(c) = 0

    Here, p(x) = x2 – k and x = 7 is the zero of p(x).

    ⇒ p (7) = 0

    ⇒ 72 – k = 0

    ⇒ k = 49

     

  • Question 7
    1 / -0

    The sides of a rectangular park are in the ratio 3 : 2 and its area is 3750 square metres. The total cost of fencing the park at 50 paise per metre is

    Solution

    Assume that the sides of the rectangle are 3a and 2a.
    Area = 3a × 2a = 6a2 = 3750 square metres
    a2 = 625
    ⇒ a = 25 m
    Perimeter = 2 × (3a + 2a) = 2 × 5a = 2 × 5 × 25 = 250 m
    Total cost of fencing = 250 × 1/2 = Rs. 125

     

  • Question 8
    1 / -0

    Length and width of a rectangle are in the ratio 5 : 2. If the sum of length and width is 63 units, what will be the width and length of the rectangle respectively?

    Solution

    Let the length and width of a rectangle be 5x and 2x.
    2x + 5x = 63
    7x = 63
    x = 9
    So, width = 2 x 9 = 18 units
    Length = 5 x 9 = 45 units

     

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