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SAT (Stage-1) Mock Test - 37

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SAT (Stage-1) Mock Test - 37
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  • Question 1
    1 / -0

    If the sum of the first 5 terms of an AP is 160 and its first term is 6, find the common difference.

    Solution

    Here, a = 6, n = 5 and Sn = 160
    Therefore, 160 = 5/2[2×6+(5 - 1)d] 
    160×2/5 = 12 + 4d
    64 – 12 = 4d
    52/4 = d
    d = 13

     

  • Question 2
    1 / -0

    The probability that a leap year selected at random will contain 53 Sundays is

    Solution

    A leap year has 366 days.
    366/7 = 52, remainder = 2
    ⇒ There are 52 weeks.
    ⇒ 52 Sundays, 2 days extra;
    For 53 Sundays, either one of these should be a Sunday.
    So, P (53 Sundays) = P (1st day is Sunday) + P (2nd day is Sunday)
    = (1/7) + (1/7) = 2/7

     

  • Question 3
    1 / -0

    If α, β are the roots of the equation 2x2 - 7x + 5 = 0, then α3 + βis equal to

    Solution

    α + β = 7/2, αβ = 5/2 (Sum and Product of roots)
    So, α2 + β2 = (α + β)2 - 2αβ = (7/2)2 -2 x 5/2 
    = 49/4 - 5 = 29/4
    α+ β= (α + β) (α2 + β2 - αβ)
    = 7/2×(29/4 –5/2)
    = 133/8

     

  • Question 4
    1 / -0

    Work efficiency of two persons is in the ratio 2 : 3. Work assigned to them is in the ratio 4 : 5. Find the ratio of the time taken by them, if they start at the same time.

    Solution

    According to the given condition,
    Let work efficiency of A be 2x and that of B be 3x.
    Work done by A is 4y and that by B be 5y.
    Ratio of time taken by them is:
    4y/2x : 5y/3x = 2 : 5/3 = 6 : 5

     

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