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Time and Work Test - 3

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Time and Work Test - 3
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  • Question 1
    1 / -0

    If 5 men or 9 women can do a piece of work in 19 days, how long will it take to complete the same work with 3 men and 6 women?

    Solution

    5 men or 9 women (5 M = 9 W) can do the job = 19 days (Given)  3M = 27/5 W
    3 men and 6 women = (27/5 + 6 ) = 57/5 women
    ∴ Time taken by 57/5 women to complete the work = 19 × 9 × 5/57 = 15 days

     

  • Question 2
    1 / -0

    A tank can be emptied by three taps in 3 hours. The first tap alone can empty it in 6 hours and second tap alone can empty it in 9 hours. How many hours will the third tap alone take to empty the tank?

    Solution

    Time taken by the first tap to empty the tank = 6 hours
    Time taken by the second tap to empty the tank = 9 hours
    Let the time taken by the third tap = `t` hr

    According to the question,
    1/6 + 1/9 + 1/t = 1/3
    ⇒ 1/t = 1/3 - 1/6 - 1/9
    ⇒ 1/t = (6 - 3 - 2)/18 = 1/18
    ⇒ t = 18 hours

     

  • Question 3
    1 / -0

    20 men could do a piece of work in 30 days working 4 hours a day, 30 men worked for 20 days for 3 hours a day. Then all were laid off, except one. How many more days would it take the last man to complete the remaining work, working 10 hours a day?

    Solution

    Let work done by 1 man in 1 hour = w

    As 20 men, working 4 hours a day, take 30 days to get the work done,
    Total work = 20 x 4 x 30 x w

    Now, by working 3 hours a day, work accomplished by 30 men in 20 days = 3 x 30 x 20 x w
    Work left to be done = 20 x 4 x 30 x w - 3 x 30 x 20 x w = 20 x 30 x w

    Now, let the last man take d days to complete the work.
    So, d x 10 x w = 20 x 30 x w
    Or, d = 60

    Thus, the last man would take 60 days.

     

  • Question 4
    1 / -0

    It was estimated that 20 men would complete a work in 50 days working for 5 hours a day. But after 15 days from the start of work, 10 men dropped out of work. How many hours per day did the remaining men have to work to complete the work on time?

    Solution

    M1D1H1 = M2D2H2

    20 × 50 × 5

    = 20 × 15 × 5 + 10 × 35 × H

    ⇒ H = 10 hours

     

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