Coordinate Geometry Test - 2

The perpendicular distance of the point (6, –5) from the x-axis will be y-coordinate but with a positive sign as distance is never negative.
So, the perpendicular distance of (6, –5) from the x-axis is 5 units.

The point (0, 3) ↔ (x, y)
Here, the x-coordinate is 0 and the y-coordinate is 3.

∴ The point (0, 3) lies on the positive y-axis.

The y co-ordinate is also known as ordinate and b is the y co-ordinate of point (a, b).
So, `b` is called ordinate.

The point is (17, 9) ↔ (x, y)

Here, x > 0 and y > 0 and if x is positive and y is positive, then the point lies in the
1^st quadrant.

So, point (17, 9) lies in the first quadrant.
OR
The sign of co-ordinate of a point is (+, +), which lies in 1^st quadrant.

So, (17, 9) lies in the first quadrant.

As the point is (8, 0)
(8, 0) ↔ (x, y)

Here, x-coordinate is 8 which is greater than 0 and y-coordinate is 0, and when y-coordinate is 0, then the point lies on x–axis.

As the x-coordinate is greater than 0, the point (8, 0) lies on positive x–axis.

The perpendicular distance from y–axis of any point is x co-ordinate but distance is always positive.
So, the perpendicular distance of (– 7, 9) from y–axis is 7 units.

The point is (11, – 15).

Here, x-coordinate is 11 > 0 and y-coordinate is – 15 < 0, and the signs of the coordinates are (+, –),

which lie in the 4^th quadrant.

So, the point (11, – 15) lies in the 4^th quadrant.

When x-coordinate is 0, the point lies on the y–axis.
∴ The point (0, 6) lies on the positive y–axis.

The perpendicular distance from y–axis of any point is x co-ordinate, but the distance can never be negative.
So, the perpendicular distance of (13, 12) from y–axis is 13.

The point is (– 7, 6).

Here, x co-ordinate is – 7 < 0 and y co-ordinate is 6 > 0
i.e. x < 0 and y > 0, and when x is negative and y is positive, then the point lies in 2^nd quadrant.

So, the point (– 7, 6) lies in the 2^nd quadrant.