Quadrilaterals Test - 1

∠Q + ∠R = 180^o [∵ Adjacent angles of a parallelogram are supplementary.]

We know that ∠M + ∠N + ∠O + ∠P = 360^o ( Angle sum property of a quadrilateral )
∠M + 180° + ∠P = 360° [Given: ∠N + ∠O = 180°]

50° + 180° + ∠P = 360°
∠P = 360° – 230°
∠P = 130°

The correct option is (4) because the diagonals of a square and a rhombus bisect each other perpendicularly.

∠A = ∠C [∵Opposite angles of a parallelogram are equal.]⇒ ∠C = 70°
And ∠A + ∠B + ∠C + ∠D = 360° [Angle sum property of a quadrilateral]

70^o + ∠B + 70^o + ∠D = 360°
∠B + ∠D = 360° – 140°
= 220°

Alternate method:
∠A + ∠B = 180° [Adjacent angles of a parallelogram are supplementary.]
70° + ∠B = 180°
∠B = 110°

Also, ∠D = ∠B [Opposite angles of a parallelogram]
∠D = 110°
∴ ∠B + ∠D = 110° + 110° = 220°