Quadrilaterals Test

Result

Quadrilaterals Test - 10

Score
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Rank
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TIME Taken - -

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Question 1
1 / -0

Five of the angles of a hexagon are equal to each other and each is greater than the remaining angle by 72°. The size of the smallest angle is

A
120°

B
108°

C
70°

D
60°

Solution

Let each of the 5 equal angles = x
Hence, sixth angle = x - 72
Sum of the angles of hexagon = 6x - 72
Sum = (2 × 6 - 4) × 90
= 720
6x - 72 = 720
6x = 792
x = 132
Hence, the smallest angle = 132 - 72 = 60°
Question 2
1 / -0

If the sum of the interior angles of a polygon is three times that of an octagon, then the number of sides of the polygon is

A
18

B
19

C
20

D
21

Solution

Sum of angles of octagon = (2 × 8 - 4) × 90 = 12 × 90
= 1080
Hence, the sum of angles of the given polygon
= 3 × 1080
= 3240
So, (2n - 4) × 90° = 3240o
(2n - 4) × 90 = 3240
2n - 4 = 3240/90 = 36
2n = 40 ⇒ n = 20