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Quadrilaterals Test - 9

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Quadrilaterals Test - 9
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  • Question 1
    1 / -0

    If the angles of a pentagon are x°, 2x°, 2x°, 2x°, 3x°, then the value of x is

    Solution

    Sum of angles of a pentagon = (2 × 5 - 4) 90
    = 6 × 90
    = 540°
    Sum of the given angles = 10x
    10x = 540°
    x = 54°

     

  • Question 2
    1 / -0

    If the sum of the interior angles of a polygon is 30 right angles, then the number of sides is

    Solution

    Sum of the angles of polygon = (2n - 4)  90
    Hence, (2n - 4) × 90 = 30 × 90
    Or (2n - 4) = 30
    2n = 34
    n = 17

     

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