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Algebra Test - 8

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Algebra Test - 8
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  • Question 1
    1 / -0

    If x = 2, y = 3 and z = 5, find the value of x2yz + xy2 + (y - zx) + (z - yx) + (x - yz).

    Solution

    x2yz + xy2 z + (y - zx) + (z - yx) + (x - yz)
    Putting x = 2, y = 3 and z = 5, we get
    = (2)2 (3) (5) + (2) (3)2 (5) + (3 - (5)(2)) + (5 - (2)(3)) + (2 - (3)(5))
    = 60 + 90 + (-7) + (-1) + (-13)
    = 150 - 7 - 1 - 13
    = 150 - 21
    = 129

     

  • Question 2
    1 / -0

    Find the value of 2abc + a2 + b2 + c2 at a = 2, if b = -1 and c = -3.

    Solution

    2abc + a+ b+ c2
    a = 2, b = -1, c = -3
    = 2 (2) (-1) (-3) + (2)2 + (-1)2 + (-3)2
    = 12 + 4 + 1 + 9
    = 26

     

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