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Mensuration Test - 2

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Mensuration Test - 2
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  • Question 1
    1 / -0

    If the total surface area of a cube is 54 m2, then its lateral surface area is equal to

    Solution

    Total surface area of the cube = 6a2
    54 m= 6a2
    54/6m2 = a2
    9 m= a2
    a = 3m [∵ Length cannot be negative.]
    Now, lateral surface area of the cube = 4a2
    = 4 (3)m2
    = 4 × 3 × 3 m2
    = 36 m2

     

  • Question 2
    1 / -0

    If each edge of a cube is 'a', then its total surface area is

    Solution

    Each edge of the cube = a
    Total surface area of the cube = Sum of areas of all the faces of the cube
    All the 6 faces of the cube are of the same dimension.
    Area of top face = (side)2 = a2
    Area of bottom face = a2
    Area of left face = a2
    Area of right face = a2
    Area of front face = a2
    Area of back face = a2
    ∴ Total surface area = a2 + a2 + a2 + a2 + a2 + a2 = 6a2

     

  • Question 3
    1 / -0

    Find the lateral surface area of a cube of edge 10 cm.

    Solution

    Lateral surface area (LSA) of a cube = 4a2 (where 'a' is the edge of the cube)
    ∴ LSA of the given cube = 4(10 cm)2
    = 4(100) cm2
    = 400 cm2

     

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