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Polynomials Test - 12

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Polynomials Test - 12
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Find the product of (6x2 + y) and (3x).

    Solution

    (6x2 + y) × (3x) = 18x3 + 3xy

     

  • Question 2
    1 / -0

    Find the coefficient of y in the equation 4x2 - 5/3y - 6.

    Solution

    Coefficients are constant factors that multiply a variable or powers of a variable.
    So, coefficient of 'y' is -5/3.

     

  • Question 3
    1 / -0

    Find the value of 2a2b if a = 3 and b = 6.

    Solution

    a = 3 and b = 6
    2a2b
    = 2 x (3)2 x 6
    = 2 x 9 x 6
    = 108

     

  • Question 4
    1 / -0

    Which of the following is a trinomial?

    Solution

    (2x + 1)(2x + 1) = 4x2 + 4x + 1
    It is a trinomial, an algebraic expression having three terms.

     

  • Question 5
    1 / -0

    Find the difference between the following two expressions:

    2x2 + 3xy - 2xyz + 7y and x2 - 7xyz + xy

    Solution

    2x2 + 3xy - 2xyz + 7y - (x2 - 7xyz + xy)
    = 2x2 + 3xy - 2xyz + 7y - x2 + 7xyz – xy
    = (2x2 – x2) + (3xy – xy) + (- 2xyz + 7xyz) + 7y
    = x2 + 2xy + 5xyz + 7y

     

  • Question 6
    1 / -0

    The length of a rectangular field is ab + b2 and its width is 2b. Find the area of the field if a and b are both smaller than 1.

    Solution

    Area = Length x Width
    = (ab + b2)(2b) = 2ab2 + 2b3

     

  • Question 7
    1 / -0

    Find the perimeter of the square whose side is 3a2b, where a and b are both greater than 1.

    Solution

    Perimeter = 4 x Side
    = 4 x 3a2b
    = 12a2b

     

  • Question 8
    1 / -0

    There is a square playground whose side is 7ab2. What is the area of that playground if a, b > 1?

    Solution

    Area of the square playground = Side2 = (7ab2)2 = 49a2b4

     

  • Question 9
    1 / -0

    A rectangular field has length 5a2 + 2b and width 2a + b. Find its area.

    Solution

    Area of rectangular field = Length x Width
    = (5a2 + 2b) x (2a + b)
    = 5a2(2a + b) + 2b(2a + b)
    = 10a3 + 5a2b + 4ab + 2b2

     

  • Question 10
    1 / -0

    Find the area of a square with side 4a + 5b.

    Solution

    Area of square = (4a + 5b)2
    (a + b)2 = a2 + b2 + 2ab
    So, (4a + 5b)2 = (4a)2 + (5b)2 + 2(4a)(5b) = 16a2 + 25b2 + 40ab

     

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