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Heron`s Formula Test - 1

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Heron`s Formula Test - 1
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  • Question 1
    1 / -0

    Perimeter of a rectangle is 18 cm. If its length is 4 cm, which of the following measures represents its breadth?

    Solution

    Perimeter of rectangle = 2 (l + b), where l = length of rectangle and b = breadth of rectangle
     18 cm = 2 (l + b)
    ⇒ 18 cm = 2(4 + b)
    ⇒ 18/2 = (4 + b)
    ⇒ 9 = 4 + b
    ⇒ 9 – 4 = b
    ⇒ b = 5 cm

     

  • Question 2
    1 / -0

    Perimeter of a rectangle is 28 cm. If the length of rectangle is 4 cm more than its breadth, find the length of the rectangle.

    Solution

    Let the breadth of the rectangle be 'b' cm.
    Length of the rectangle = b + 4 cm

    Perimeter = 2(l + b)
    28 = 2(b + 4 + b)

    28/2 = 2b + 4
    14 = 2b + 4

    14 – 4 = 2b
    ⇒ b = 10/2
    ⇒ b = 5 cm

    So, length of rectangle = 5 + 4 = 9 cm

     

  • Question 3
    1 / -0

    If perimeter of a square is 32 cm, find its side.

    Solution

    Perimeter of square = 4a, where 'a' is the side of the square.
    ⇒ 32 = 4a
    ⇒ 32/4 = a
    ⇒ a = 8 cm

     

  • Question 4
    1 / -0

    Area of a rectangle is 36 cm2. What would be the side of the square if its perimeter is equal to the area of the given rectangle?

    Solution

    Given: Perimeter of the square = Area of the rectangle
    ⇒ 4a = 36 (given)
    ⇒ a = 36/4
    ⇒ a = 9 cm

    Hence, side of the square = 9 cm

     

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