Sainik School Entrance Book Class 9 AISSEE (Paper-2) Mock-3 Download PDF

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AISSEE (Paper-2) Mock-3

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Weekly Quiz Competition

Question 1
2 / -0

In the following question, there is some relationship between the two groups on the left of (: :) and the same relationship exists between the two groups on its right. Find the missing group.

EIGHTY : GIEYTH : : OUTPUT : ?

A
TUOTUP

B
TUOUTP

C
UTOPTU

D
UOTUPT

Solution

The first three and the last three letters of the first group are separately reversed in order to obtain the second group.
EIGHTY >> (EIG)(HTY) >> (GIE)(YTH) >> GIEYTH
OUTPUT >> (OUT)(PUT) >> (TUO)(TUP) >> TUOTUP
Question 2
2 / -0

In the following question, there is a relationship between the two terms to the left of : : and the same relationship holds between the two terms to its right. One term is missing. One of the four given options contains the missing term. Identify the correct option.

ADC : EHG : : MPO : ___________

A
QTR

B
QTS

C
QST

D
QRT

Solution

A (+4) E

D (+4) H

C (+4) G

M (+4) Q

P (+4) T

O (+4) S
Question 3
2 / -0

There is some relationship between the two terms to the left of the sign (: :). The same relationship exists between the two terms to its right, out of which one is missing. Find the missing term from the given alternatives.

8 : 16 : : 40 : ___

A
40

B
80

C
20

D
10

Solution

The relationship is n : 2n.
The missing number = (40 × 2) = 80
Question 4
2 / -0

In the following question, there is a certain relationship between the two terms given to one side of (: :) and one term is given to the other side of (: :), while another term of this pair is to be found from the given alternatives having the same relationship with this term as the terms of the given pair bear. Choose the best alternative.

1024 : 14 : : 1216 : ?

A
32

B
20

C
8

D
10

Solution

1 + 0 + 2 + 4 = 7 and 7 × 2 = 14
Similarly, ? = 1 + 2 + 1 + 6 = 10 and 10 × 2 = 20
Question 5
2 / -0

Given below is a series with one or two terms missing. Choose the correct alternative from the given options that will complete the series.

G8, H13, I18, __, K28

A
I21

B
J20

C
J23

D
J25

Solution

Sequence → The letters move ahead by 1 place and the numbers go up by 5.
I18 - J23
Question 6
2 / -0

In the following question, a series is given with one or two terms missing. Choose the correct alternative from the given options that will complete the series.

9, 12, 11, 14, 13, __, 15

A
14

B
16

C
18

D
20

Solution

The sequence consists of two series: 9, 11, 13, 15 and 12, 14, 16.
Question 7
2 / -0

In the following question, a number series is given with one term missing. Choose the correct alternative that will continue the same pattern in the given series.

165, 195, 255, 285, 345, ___

A
365

B
405

C
415

D
375

Solution

The sequence is + 30, + 60, + 30, + 60.
The missing number is 345 + 30 = 375.
Question 8
2 / -0

In the given question, which character when placed at the sign of interrogation will complete the matrix?

A D G

D I N

I P ?

A
V

B
W

C
X

D
Y

Solution

The pattern followed is row wise as shown below:
1st row: A + 3 = D + 3 = G
2nd row: D + 5 = I + 5 = N
3rd row: I + 7 = P + 7 = W
Therefore, the missing letter is W.
Question 9
2 / -0

In the given question, which term when placed at the sign of interrogation will complete the matrix?

4C 2B 3A

28A ? 45B

7C 5A 15B

A
10C

B
12C

C
13C

D
7C

Solution

In the each row, out of the letters A, B and C, each of these must appear once.
So the missing letter is C.

Now, the middle number in each column is product of the other two numbers in the column.
So the missing number is 2 × 5 = 10

Therefore, the missing element is 10C.
Question 10
2 / -0

In a row of students, Atul is 15^th from the front and 6^th from the back. Find the total number of students in the row.

A
22

B
21

C
20

D
23

Solution

Number of students before Atul = 14
Number of students after Atul = 5
Total number of students in the row = 14 + 5 + 1 = 20
Question 11
2 / -0

Find the number which, when added to itself 13 times, gives 112.

A
7

B
8

C
9

D
11

Solution

Let the number be x.
According to the question:
x + (x + x ...13 times) = 112
So, 14x = 112
x = 8
Question 12
2 / -0

The average temperature of a town in the first six days of a month was 41°C and the sum of the temperatures of the first five days of the same month was 201°C. What was the temperature on the sixth day of the month?

A
40°C

B
45°C

C
46°C

D
50°C

Solution

Here the average temperature of first 6 days is given as 41°C and we can calculate the sum total of temperatures of 6 days by multiplying 41 with 6, which is 246°C.
Sum total of temperatures of first 5 days = 201°C
So, we will subtract 201 from 246 and the answer is 45°C.
Question 13
2 / -0

In the following question, arrange the given words in the sequence in which they occur in the dictionary and then choose the correct sequence.

1. Protein
2. Problem
3. Proverb
4. Property
5. Project

A
1, 2, 3, 4, 5

B
2, 1, 4, 3, 5

C
2, 5, 4, 1, 3

D
3, 4, 5, 2, 1
Question 14
2 / -0

If in a certain code language, ENGLAND is written as 1234526 and FRANCE is written as 785291, then how is GREECE written in that language?

A
381171

B
381191

C
832252

D
835545

Solution

Each letter has a different code as shown:

Letters E N G L A N D

Codes 1 2 3 4 5 2 6

Letters F R A N C E

Codes 7 8 5 2 9 1

GREECE is coded as 381191.
Question 15
2 / -0

In the year 1648, if February had 5 Sundays, then what was the day on 13^thFebruary, 1750?

A
Sunday

B
Friday

C
Saturday

D
Monday

Solution

Since February had 5 Sundays in 1648; therefore, 1^st February, 1648 was a Sunday.
Number of odd days up to 1^st February,
1748 = 5
Number of odd days from 1^st February, 1748 to 1^st February, 1750 = (2 + 1) = 3
Number of odd days from 1^st February, 1750 to 13^th February, 1750 = 12
So, total number of odd days = 5 + 3 + 12 = 20 = 6 odd days
So, the answer is Saturday.
Question 16
2 / -0

Which of the following years has the same calendar as 1700?

A
1704

B
1705

C
1706

D
1707

Solution

Year: 1700 1701 1702 1703 1704 1705

Number of odd days 1 1 1 1 2 1

Total number of odd days from 1700 to 1705 is remainder(7/7) i.e. 0.
It means next of 1705 i.e 1706 is the same as 1700.
Question 17
2 / -0

From the given alternatives, select the word which cannot be formed using the letters of the given word.

Accomplishment

A
Cache

B
Month

C
Chance

D
Serpent

Solution

As there is no 'r' in the word 'accomplishment', so the word 'serpent' cannot be formed.
Question 18
2 / -0

From the given words, select the word which cannot be formed using the letters of the given word.

JOSTLING

A
INLET

B
GLINT

C
INGOT

D
JINGO

Solution

In the word JOSTLING, there is no letter E. So, INLET cannot be formed using the letters of this word.
Question 19
2 / -0

What will be the value of 23 ÷ 89 + 4 × 18 - 3 if '-' means '×', '+' means '÷', '×' means '+' and '÷' means '-'?

A
67.80

B
61.25

C
57.75

D
54.75

Solution

After writing the proper notations, we get 23 - 89 ÷ 4 + 18 × 3
= 23 - 22.25 + 54
= 0.75 + 54
= 54.75
Question 20
2 / -0

Pointing to a man in a photograph, a woman said, ''His brother's father is the only child of my grandfather.'' How is the woman related to the man in the photograph?

A
Sister

B
Mother

C
Aunt

D
Daughter

Solution

The only child of the woman's grandfather is the woman's father. The woman's father is the same as the man's father. So, the woman is the man's sister.

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Re-Attempt Weekly Quiz Competition

Year:	1700	1701	1702	1703	1704	1705
Number of odd days	1	1	1	1	2	1

A	(+4)	E
D	(+4)	H
C	(+4)	G

M	(+4)	Q
P	(+4)	T
O	(+4)	S

4C	2B	3A
28A	?	45B
7C	5A	15B

Letters	E	N	G	L	A	N	D
Codes	1	2	3	4	5	2	6

AISSEE (Paper-2) Mock-3

Result

AISSEE (Paper-2) Mock-3

Score

-

Rank

-

SHARING IS CARING

Question 1

TUOTUP

TUOUTP

UTOPTU

UOTUPT

Solution

Question 2

QTR

QTS

QST

QRT

Solution

Question 3

40

80

20

10

Solution

Question 4

32

20

8

10

Solution

Question 5

I21

J20

J23

J25

Solution

Question 6

14

16

18

20

Solution

Question 7

365

405

415

375

Solution

Question 8

V

W

X

Y

Solution

Question 9

10C

12C

13C

7C

Solution

Question 10

22

21

20

23

Solution

Question 11

7

8

9

11

Solution

Question 12

40°C

45°C

46°C

50°C

Solution