Mathematics Tes...

Find the value of the following integral.

\(\int_{0}^{\frac{\pi}{2}} \frac{\sqrt{\cos x}}{\sqrt{\sin x}+\sqrt{\cos x}} d x\)

The area bounded by the curve y = 2x - x² and the straight line y = - x is given by

The area of the region bounded by y = | x - 1 | and y = 1 is

The area bounded by the curve y = x | x |, x-axis and the ordinates x = 1, x = -1 is given by

The area lying in the first quadrant and bounded by the circle x² + y² = 4, the line x =√3 y and the x-axis is

The area under the curve y = sin 2x + cos 2x between x = 0 and x = π/4 is

The area of the region bounded by the curve y² = 4x, y-axis and the line y = 3 is

The area of the figure bounded by y = sin x, y = cos x in the first quadrant is

The area bounded by curve xy = c and x-axis between x = 1 and x = 4, is

If n(U) = 20, n(A) = 12, n(B) = 9, n(AB) = 4, where U is the universal set, A and B are subsets of U, then n | (A U B)^o| is equal to

Period of cot 3 x - cos (4x + 3) is

sin 30° + cos 60° + tan 45° is equal to

The value of sin 10° + sin 20° + sin 30° + ........+ sin 360° is

α and β lie between 0 and π/4, cos(α + β) = 12/13 and sin(α - β) = 3/5.

sin 2α =

(tan 3x - tan 2x - tan x) is equal to