Chemistry Test

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Chemistry Test - 17

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following states of matter has least number of particles per unit area?

A
Solids

B
Liquids

C
Gases

D
All of the above

Solution

Gases are the states of matter which has least density as the particles are very far away and so molecules per unit area are very less.
Question 2
1 / -0

In order to fully separate metals in an ore sample, the sample is heated to extremely high temperatures the various processes are used to separate the metal components.

Which of the following would give the least amount of usable information for developing an extraction method for lead from other metals in an ore sample?

A
A heating and cooling curve for pure substances which provides information on the energetics of the phase changes indicating optimum temperature for re-solidification of each pure metal.

B
Knowledge of the viscosity of the various pure substances at elevated temperatures that could be used to determine if the pure metals can be separated by distillation techniques.

C
Reactions of the various pure metals with non-soluble ions in solution at temperatures cool enough to precipitate out the lead ions as part of non-soluble compound.

D
Knowledge of the inter and intramolecular forces exhibited by the pure metals when coupled with other substances at very high temperatures not already present in the ore.

Solution

Lead has high boiling point. Nearly 1800^o C. But some metals have less boiling point than lead. If other metals are heated to their boiling point and separated and then cooled, they will separate and metals obtains as solids. So, if we know heating and cooling curves, we can separate them easily.
Question 3
1 / -0

In the rusting of iron, 4Fe + 3O₂ → 2Fe₂O₃, iron is:

A
reduced

B
oxidised

C
precipitated

D
hydrolysed

Solution

In the process of rusting of iron, iron is oxidized as oxygen is added to iron 4Fe + 3O₂→ 2Fe₂O₃. Because of the addition of oxygen, it is termed as oxidation.
Question 4
1 / -0

The mass of 3.01 × 10²³ molecules of a gas is 32.0 g. What volume does 8.00 g of the gas occupy at STP?

A
2.80 L

B
8.00 L

C
11.2 L

D
22.4 L

Solution
Question 5
1 / -0

Monomer used to prepare orlon is:

A
CH₂ = CHCN

B
CH2 = CH − CI

C
CH₂= CHF

D
CH₂ = CCI₂

Solution

Orlon is the one of the polymer created by DuPont in the year 1941. These are strong and warm used for sweaters and tracksuits.

The monomer of this polymer Orlon is a acrylonitrile [CH₂ = CHCN].
Question 6
1 / -0

From the following which is not a surface phenomenon?

A
Corrosion

B
Crystallisation

C
Heterogeneous catalysis

D
Water and its vapour in a closed vessel

Solution

The phenomenon that takes place at the surface, are termed as surface phenomenon. Among the given processes, crystallisation, takes place in the bulk, not at the surface, so it is not a surface phenomenon.
Question 7
1 / -0

According to Dobereiner in Triads, atomic weight of the centre element is equal to __________ 1st and 3rd elements in that triads.

A
Geometric Mean

B
Arithmetic Mean

C
Harmonic Mean

D
None of these

Solution

Döbereiner's triads were an early attempt to sort the elements into some logical order by their physical properties. It was discovered by reported Johann Wolfgang Döbereiner's in 1817.He also noted that quantifiable properties of elements (e.g. atomic weight and density) in a triad followed a trend whereby the value of the middle element in the triad would be exactly or nearly predicted by taking the arithmetic mean of values for that property of the other two elements.
Question 8
1 / -0

The placement of elements in the Newlands' table was compared to :

A
weeks of a month

B
notes of music

C
months of a year

D
days of a month

Solution

The placement of elements in the Newlands' periodic table was compared to the notes of music where the first note and the eighth note are same. Similarly, in Newlands' periodic table, the chemical properties also repeat after 7 elements.
Question 9
1 / -0

Sub atomic particles are?

A
electrons

B
protons

C
neutrons

D
all the above

Solution

In an atom, the sub atomic particles are electrons, protons and neutrons. These are present in an atom so they are called sub atomic particles.
Question 10
1 / -0

Which of the following is known as invert soap?

A
Pentaeryth ritol monostearate

B
Sodium stearyl sulphate

C
Trimethlsteary ammonium bromide

D
Ethoxylated nonyphenol

Solution

Invert soaps are a class of synthetic detergents in which the surface-active part of the molecule is the cation. One of the invert soap is trimethylsteary ammonium bromide.

Hence option C is correct.

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Chemistry Test - 17

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Chemistry Test - 17

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Question 1

Solids

Liquids

Gases

All of the above

Solution

Question 2

A heating and cooling curve for pure substances which provides information on the energetics of the phase changes indicating optimum temperature for re-solidification of each pure metal.

Knowledge of the viscosity of the various pure substances at elevated temperatures that could be used to determine if the pure metals can be separated by distillation techniques.

Reactions of the various pure metals with non-soluble ions in solution at temperatures cool enough to precipitate out the lead ions as part of non-soluble compound.

Knowledge of the inter and intramolecular forces exhibited by the pure metals when coupled with other substances at very high temperatures not already present in the ore.

Solution

Question 3

reduced

oxidised

precipitated

hydrolysed

Solution

Question 4

2.80 L

8.00 L

11.2 L

22.4 L

Solution

Question 5

CH2 = CHCN

CH2 = CH − CI

CH2 = CHF

CH2 = CCI2

Solution

Question 6

Corrosion

Crystallisation

Heterogeneous catalysis

Water and its vapour in a closed vessel

Solution

Question 7

Geometric Mean

Arithmetic Mean

Harmonic Mean

None of these

Solution

Question 8

weeks of a month

notes of music

months of a year

days of a month

Solution

Question 9

electrons

protons

neutrons

all the above

Solution

Question 10

Pentaeryth ritol monostearate

Sodium stearyl sulphate

Trimethlsteary ammonium bromide

Ethoxylated nonyphenol

Solution

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CH₂ = CHCN

CH₂= CHF

CH₂ = CCI₂