Chemistry Test - 34

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Chemistry Test - 34

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Weekly Quiz Competition

Question 1
1 / -0

The final product of the following sequence of reactions

A
3-ethyl-2-methyl-l-hexanol

B
2,3-dimethyl-l-pentanol

C
2-ethyl-3-methyl-l-hexanol

D
3,3-dimethyl-l-pentanol

Solution
Question 2
1 / -0

Two containers P and Q of equal volume (1 liter each) contain 6 g of O₂ and SO₂ respectively at 300 K and 1 atmosphere. then

A
Number of molecules in P is less than that in Q

B
Number of molecules in P and Q is same

C
Number of molecules in Q is less than that in P

D
Either [a] or [b]

Solution

Mol. of \(O_{2}=\left(\frac{6}{32}\right) \& \mathrm{mol}\). of \(S O_{2}=\frac{6}{64}\). The number o molecules of \(S O_{2}\) will be less than that of \(O_{2}\)
Question 3
1 / -0

Galvanic cell involves

A
conversion of thermal energy (Heating) into electrical energy

B
conversion of electrical energy into chemical energy

C
conversion of chemical energy into thermal energy

D
conversion of chemical energy into electrical energy

Solution

Galvanic cell is electrochemical cell in which emf is generated at the cost of reduction- oxidation.
Question 4
1 / -0

Drawback of DDT as pesticide is that

A
it becomes ineffective after some time

B
it is less effective than others

C
it is not easily/rapidly degraded in nature

D
its high cost

Solution

DDT?a pesticide, is not easily and rapidly degraded in nature.
Question 5
1 / -0

A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number of moles of all the gases is 10. If the partial pressures of A and B are 3.0 and 1.0 atm respectively and if 'C" has mol. wt of 2.0 what is the weight of 'C' in g present in the mixture.

A
8

B
12

C
3

D
6

Solution

Total pressure of mixture of gases A,B & C = 10 atm. Partial pressure of A = (No. of moles of Ax 10)/10 or (No. of moles of A x10) / 10 = 3 Hence, no. of moles of A= 3
∴Partial pressure of B = (No. of moles of Bx10) /10 (since partial pressure of B=1 atm)
∴No. of moles of B = 1 Now the no. of moles of C = 10 - (3+1) = 6; mole of C weighs = 2 gm.
∴6 mole of C will weigh = 2 x 6 = 12
Question 6
1 / -0

The molecule of ortho hydrogen is distinguished from para hydrogen by

A
two electrons moving in opposite directions

B
two electrons moving in the same directions

C
two protons revolving in opposite directions

D
two protons revolving in the same directions

Solution

In ortho hydrogen, proton revolve in the same direction.
Question 7
1 / -0

During bromination of benzene in the presence of FeBr₃ the species that attacks the ring to initiate the process is

A
FeBr⁻₄

B
Br⁺

C
Br⁻

D
Br₂ molecule

Solution

The metallic halide (Lewi acid) polarises the halogen molecule to yield the electrophite \(X^{+}\) (haloniumion \() F e B r_{3}+B r_{2} \rightarrow F e B r_{4}^{-}+B r^{+}\)
Question 8
1 / -0

A and B in the reaction,

A

B

C

D

Solution
Question 9
1 / -0

Which of the following salts is colourless?

A
CdCl₂

B
CuSO₄ ⋅ 5H₂O

C
MnSO₄ ⋅ 7H₂O

D
NiSO₄⋅ 7H₂O

Solution

CdCl₂ has Cd²⁺ ion (4d¹⁰), which is colourless.
Question 10
1 / -0

Which of the following rate laws has an overall order of 0.5 for reaction involving substances x, y and z?

A
Rate= k(C_x) (C_y) (C_z)

B
Rate= k(Cx)^0.5 (Cy)^0.5 (Cz)^0.5

C
Rate= k(Cx)^1.5 (Cy)⁻¹ (Cz)⁰

D
Rate= k(Cx) (Cy)^0.5 / (Cz)²

Solution

Rate= k(Cx)^1.5(Cy)⁻¹ (Cz)⁰ Order = sum of all exponential term =1.5 + (−1)= 0.5