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Aldehydes Ketones and Carboxylic Acids Test - 73

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Aldehydes Ketones and Carboxylic Acids Test - 73
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  • Question 1
    1 / -0
    $$CH_3 - \underset{O}{\underset{||}{C}} - OH \xrightarrow[]{NaH{\overset{14}{C}O_3}} (P \,gas) \xrightarrow[(2) H_3O^{\oplus}]{(1)PhCH_2MgBr} (Q)$$

    $$CH_{ 3 }-\overset { O }{ \overset { || }{ \underset { O }{ \underset { || }{ S }  }  }  } -OH\xrightarrow [  ]{ NaH{ \overset { 14 }{ C } O_{ 3 } } } (R\, gas)\xrightarrow [ (2)H_{ 3 }O^{ \oplus  } ]{ (1)Ph{ \overset { 14 }{ C }  }H_{ 2 }MgBr } (S)$$
    Product (Q) and (S) in the aove reactions are respectively:
    Solution
    $$CH_3 - \underset{O}{\underset{||}{C}} - OH \xrightarrow[]{NaH\overset{14}{C}O_3} CH_3CO\overset{-}{O} \overset{+}{N}a + H_2O + \overset{14}{C}O_2$$

    $$\overset{14}{C}O_2 \xrightarrow[(2) H_3O^{\oplus}]{(1) PhCH_2MgBr} \underset{(Q)}{PhCH_2\overset{14}{C}OOH}$$

    $$CH_3 - \overset{O}{\overset{||}{\underset{O}{\underset{||}{S}}}} - OH \xrightarrow[]{NaH\overset{14}{C}O_3} CH_3SO_3Na + H_2O + \overset{14}{C}O_2$$

    $$\overset{14}{C}O_2 \xrightarrow[(2) H_3O^{\oplus}]{(1) Ph\overset{14}{C}H_2MgBr} \underset{(S)} {Ph\overset{14}{C}H_2 \overset{14}{C}OOH.}$$

    Option C.
  • Question 2
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    Solution

  • Question 3
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    Directions For Questions

    A carbonyl compound $$P$$, which gives positive iodoform test, undergoes reaction with $$MeMgBr$$ followed by dehydration to give an olefin $$Q$$. Ozonolysis of $$Q$$ leads to a dicarbonyl compound $$R$$, which undergoes intramolecular aldol reaction to give predominantly $$S$$.
    $$P \underset {\underset {3. H_{2}SO_{4}, \triangle}{2.H^{+}, H_{2}O}}{\xrightarrow {1. MeMgBr}} Q \underset {2. Zn, H_{2}O}{\xrightarrow {1. O_{3}}} R \underset {2.\triangle}{\xrightarrow {1. OH^{-}}} S$$.

    ...view full instructions

    The structure of the product $$S$$ is
    Solution

  • Question 4
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    By the action of malonic acid in ethanolic ammonia on benzaldehyde in the presence of pyridine, it forms:
    Solution
    The reactants for this are benzaldehyde and malonic acid in the presence of a weak base, followed by acid-catalyzed decarboxylation. It can also be prepared by oxidation of cinnamaldehyde, condensation of benzal chloride and sodium acetate (followed by acid hydrolysis), and the Perkin reaction.

  • Question 5
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    In the following reaction sequence
    What is X.

    Solution

  • Question 6
    1 / -0
    Which carbonyl group is protonated most readily in acidic solution, but gives nucleophilic addition by $$NH_{2}NH-Ph$$ least readily?
    Solution

  • Question 7
    1 / -0
    What is the correct $$IUPAC$$ name for

    Solution

  • Question 8
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    Solution

  • Question 9
    1 / -0
    The $$IUPAC$$ name for $$\begin{matrix} { CH }_{ 3 }CH={ CH }{ CH }_{ 2 }{ CH }{ CH }_{ 2 }COOH \\ \quad \quad| \\ \quad \quad{ CH }_{ 2 } \end{matrix}$$ is
    Solution
    $$\begin{matrix} \overset { 7 }{ { CH }_{ 3 } }  & - & \overset { 6 }{ CH }  & = & \overset { 5 }{ CH }  & - & \overset { 4 }{ { CH }_{ 2 } }  & - & \overset { 3 }{ CH }  & - & \overset { 2 }{ { CH }_{ 2 } }  & - & \overset { 1 }{ COOH }  \\  &  &  &  &  &  &  &  & | &  &  &  &  \\  &  &  &  &  &  &  &  & { NH }_{ 2 } &  &  &  &  \end{matrix}$$
                                                 $$3-$$amino$$-5-$$heptenoice acid
  • Question 10
    1 / -0
    What is the compound called if remaining two valencies of a carbonyl group are satisfied by two alkyl groups 
    Solution
    The compound formed is known as $$Ketone.$$ And according to question, the compound so formed has a structure, $$R_2C=O. $$ And this is the general structure of ketones.
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